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Inessa [10]
3 years ago
9

What is the sum of 2+5

Mathematics
2 answers:
CaHeK987 [17]3 years ago
3 0

2 + 5 = 7...it’s basic addition but ok...

erica [24]3 years ago
3 0
7 but I’m just guessing
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Val rented a bicycle while she was on vacation. She paid a flat rental fee of f dollars, plus $8.50 each day. The total cost at
damaskus [11]

The question is incomplete. Here is the complete question:

Val rented a bicycle while she was on vacation. She paid a flat rental fee of f dollars, plus $8.50 each day. The total cost at the end of her vacation was t dollars. Let d represent the number of days Val rented the bicycle. Write an equation representing the total cost at the end of her vacation.

Answer:

t=f+8.5d

Step-by-step explanation:

Given:

Flat rental fee = f

Variable fee per day = $8.50

Total cost at the end vacation = t

Number of days of her vacation = d

Using unitary method, we can find the variable fee for 'd' days.

1 day variable fee = $8.50

Therefore, 'd' days variable fee = 8.50d

Total cost at the end of her vacation can be obtained by adding the fixed rental fee and the variable fee obtained for the given number of days.

Now, total cost is given as:

Total cost = Flat rental fee + Variable fee

Substituting all the variables and framing above in the form of an equation, we get:

t=f+8.5d

Therefore, the equation representing the total cost at the end of her vacation is t=f+8.5d

7 0
3 years ago
Which statement is modeled by the expression?
Agata [3.3K]

Answer:

the right answer is

"A store had 500 apples to be placed in bags with an equal number of apples in each bag. If n is the number of bags to be used, then 500n is the number of apples in each bag"

4 0
4 years ago
Read 2 more answers
Solve the system <br> 2x+2y+z=-2 <br> -x-2y+2z=-5<br> 2x+4y+z=0
drek231 [11]

The values of (x,y,z) are (3,-1,-2) , if the given are equations 2x+2y+z=- 2,-x-2y+2z=-5 and 2x+4y+z=0.

Step-by-step explanation:

The given is,

                          2x+2y+z=- 2.......................................(1)

                         -x-2y+2z=-5......................................(2)

                            2x+4y+z=0.........................................(3)

Step:1

           Equation (2) is multiplied by -1            ( Eqn(2) × -1 )

                                         x+2y-2z=5.............................(4)

          Subtract the equation (1) and (4)

                                        2x+2y+z=- 2

                                         x+2y-2z=5

                 ( - )

           (2x-x)+(2y-2y)+(z+2z)=(-2-5)

                                                  x+3z=-7......................(5)

Step:2

          Equation (2) is multiplied by -2                 ( Eqn(2) × -2)

                                        2x+4y-4z=10........................(6)

         Subtract equation (6) and (3),                  

                                        2x+4y-4z=10

                                         2x+4y+z=0

                   ( - )

       (2x-2x)+(4y-4y)+(-4z-z)= (10-0)

                                                     -5z=10

                                                         z = - \frac{10}{5}

                                                         z = -2

         From the equation (5),

                                                  x+3z=-7  

                                          x+(3)(-2)=-7

                                                           x = -7+6

                                                            x = -1

         From equation (1),

                                            2x+2y+z=- 2

          Substitute x and z values,

                               (2)(-1)+2y+(-2)=-2

                                                     2y - 4=2

                                                           2y=4-2

                                                           2y=2

                                                            y=\frac{2}{2}

                                                             y = 1

Step:3

                Check for solution,

                                  -x-2y+2z=-5

                Substitute x,y and z values,

               -(-1)-(2)(1)+(2)(-2)=-5

                                         1-2-4=-5

                                                    -5 = -5

Result:

              The values of (x,y,z) are (3,-1,-2) , if the given are equations 2x+2y+z=- 2,-x-2y+2z=-5 and 2x+4y+z=0.

8 0
4 years ago
Find the 14th term of the geometric sequence 2, 4, 8,
Papessa [141]

Answer:

16384

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
PLEASE HURRY!!! What is the slope of the line that passes through (4, 5) and (8, -1)
Nitella [24]

Answer:

-1.5

Step-by-step explanation:

The slope of a line is given by the formula:

m=\frac{y_2-y_1}{x_2-x_1}

Let's let (4,5) be x₁ and y₁ and let's let (8,-1) be x₂ and y₂. So:

m=\frac{-1-5}{8-4}

Subtract:

m=\frac{-6}{4}

Reduce:

m=-\frac{3}{2}=-1.5

So, our slope is -3/2 or -1.5.

And we're done!

4 0
3 years ago
Read 2 more answers
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