Answer: the anwser is 5 trust me
Step-by-step explanation:
As for this problem, it would be best to approach this with a ratio to ratio approach. This would then involve the equation with fractions which is the common conversion from ratios to easily solve the problems concerning these. The equation then would look somehow like this:
0.01 miles / 1 hour = x miles / 2.4 hours
The easiest way would be just to multiply the numerator, which is the miles, to 2.4. So when it is multiplied to the numerator, the equation then would turn to:
0.01 miles x 2.4 / 1 hour = x miles / 2.4 hours
0.024 miles would be the answer.
A = event the person got the class they wanted
B = event the person is on the honor roll
P(A) = (number who got the class they wanted)/(number total)
P(A) = 379/500
P(A) = 0.758
There's a 75.8% chance someone will get the class they want
Let's see if being on the honor roll changes the probability we just found
So we want to compute P(A | B). If it is equal to P(A), then being on the honor roll does not change P(A).
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A and B = someone got the class they want and they're on the honor roll
P(A and B) = 64/500
P(A and B) = 0.128
P(B) = 144/500
P(B) = 0.288
P(A | B) = P(A and B)/P(B)
P(A | B) = 0.128/0.288
P(A | B) = 0.44 approximately
This is what you have shown in your steps. This means if we know the person is on the honor roll, then they have a 44% chance of getting the class they want.
Those on the honor roll are at a disadvantage to getting their requested class. Perhaps the thinking is that the honor roll students can handle harder or less popular teachers.
Regardless of motivations, being on the honor roll changes the probability of getting the class you want. So Alex is correct in thinking the honor roll students have a disadvantage. Everything would be fair if P(A | B) = P(A) showing that events A and B are independent. That is not the case here so the events are linked somehow.
Answer:
- 6x³ - 1
Step-by-step explanation:
Substitute x = g(x) into f(x), that is
(f ￮ g)(x)
= f(x³ )
= - 6(x³) - 1
= - 6x³ - 1
