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Black_prince [1.1K]
3 years ago
7

An infant is brought to the clinic for his third diphtheria–tetanus toxoid–acellular pertussis vaccination (dtap). the mother re

ports that the infant developed a 99.4°f (37.4°c) temperature after the last dtap. which action is most appropriate?
Biology
1 answer:
Mumz [18]3 years ago
7 0

The correct answer is administration of vaccination.  

DTaP refers to a vaccine, which assists the younger children below the age of 7 to develop immunity against the three dreadful ailments caused by bacteria, like tetanus, diphtheria, and whooping cough.  

Mild fever after the DTaP vaccine is not unusual, thus, the vaccination should not be withheld for that reason. However, vaccination can be withheld in case of previous anaphylactic sensitivity or reaction to a component in the vaccination.  


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With a population in Hardy-Weinberg equilibrium, the A allele has a frequency of 0.60, and the frequency of the a allele is 0.40
valkas [14]

Following the Hardy-Weinberg equilibrium theory, the frequency of the heter0zyg0us genotype is 2pq. In the exposed example, 2pq = 0.48.

<h3>Hardy-Winberg equilibrium</h3>

The Hardy-Weinberg equilibrium theory states that the allelic frequencies in a locus are represented as p and q.

Assuming a diallelic gene,

→  The allelic frequencies are

  • p is the frequency of the dominant allele,
  • q is the frequency of the recessive allele.

→  The genotypic frequencies after one generation are

  • p² (H0m0zyg0us dominant genotypic frequency),
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If a population is in H-W equilibrium, it gets the same allelic and genotypic frequencies generation after generation.

The addition of the allelic frequencies equals 1  ⇒ p + q = 1.

The sum of genotypic frequencies equals 1 ⇒ p² + 2pq + q² = 1

If the allele A has a frequency of 0.6, and the allele B has a frequency of 0.4, then the frequency of the heter0zyg0us genotype is

2pq = 2 x 0.6 x 0.4 =<u> 0.48</u>

You can learn more about the Hardy-Weinberg equilibrium at

brainly.com/question/3406634

7 0
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