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3 years ago

Expand (4x-2y)^3 for math final

1 answer:

5 0

In general: (a - b)^3 = a^3 - 3 a^2b + 3 a b^2 - b^3
(4x-2y)^3 = (4x)^3 - 3 (4x)^2(2y) + 3 (4x) (2y)^2 - (2y)^3

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Desperate for help, please! Maths!

Kitty [74]

Answer:

c) m = 5p-4

Explanation:

Given that function A is : x → +4 → ×2.

A(x) = 2(x+4).

Given that function B is: x → ÷5 → +1.

B(x) = x/5 + 1.

To find the working variables for:

m → Function A → Function B → 2p + 1.

Create this composite function: B(A(x)) = 2(x+4)/5 + 1

Then set x equal to m and solve for the working equation to 2p + 1

_______________

(simplify)

2(m+4)/5 + 1 = 2p + 1

-1 -1

________________

2(m+4)/5 = 2p

÷2 ÷2

___________

(m+4)/5 = p

×5 ×5

_________

(m+4) = 5p

-4 -4

________

m = 5p - 4

5 0

3 years ago

Amount Financed (m) = $1,860 Number of Payments per year (y) = 12 Number of Payments (n) = 36 Total Interest (c) = $350.00

Luda [366]

Hi there
The formula to find I (ARP)

I=(2yc)/(m×(1+n)
I=(2×12×350)÷(1,860×(1+36))
I=0.1221×100
I=12.21%

Good luck!

8 0

3 years ago

If a soccer team won 7 of its 12 games, what was their ratio of wins to losses? Assume that there were no tie games.

Bumek [7]

Answer:

There is something missing in what you put right? Bc it doesn't make any sense. XD

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

Will Mark Brainlest

Mars2501 [29]

the discriminat of each quadratic equation : ax²+bx+c=0 ....(a ≠ 0) is :
Δ = b² -4ac
1 ) Δ > 0 the equation has two reals solutions : x = (-b±√Δ)/2a
2 ) Δ = 0 : one solution : x = -b/2a
3 ) Δ < 0 : no reals solutions

3 0

3 years ago

HELP ASAP!!!! If the point (x, V3/2) is on the unit circle, what is X?

loris [4]

Answer:

its 1/2

Step-by-step explanation:

please correct me if im wrong

5 0

4 years ago