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Reil [10]
3 years ago
11

There are 45 boys and 60 girls in Year 6. What is the ratio of boys to girls? Write the ratio in the simplest form

Mathematics
2 answers:
noname [10]3 years ago
8 0

Answer:

9:1

Explanation: 45:60 but in simpliest form you divde each by 5 and get simpliest form. I also just did this same question on a quiz and got it right

exis [7]3 years ago
6 0
The answer to this is 3:4
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It takes 4 pounds of apples to make 6 cups of applesauce.
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Answer:

Step-by-step explanation:

4lbs of apples to 6 cups of apple sauce

we can write this as 2:3

the correct choices: 6:9 and 14:21

4 0
3 years ago
Lucas took out a car loan for $14,475 that has a 0% APR for the first 16
Fiesta28 [93]

Answer:

The answer is 44 months.

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60 months - 16 months = 44

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Emilia lost $4,000 in personal belongings due to a flood at her apartment complex. Fortunately, she had renter’s insurance with
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She would receive $3500 maximum.

Since she has $10,000 in coverage, the entire $4000 loss is covered.  However, the insurance company would only pay her the amount after the deductible has been taken:

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3 years ago
How many thousands are in 5000 ones
Mashutka [201]
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5 0
3 years ago
Read 2 more answers
A diagnostic test for a disease is such that it (correctly) detects the disease in 90% of the individuals who actually have the
Ne4ueva [31]

Answer:

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Test positive

Event B: Has the disease

Probability of a positive test:

90% of 3%(has the disease).

1 - 0.9 = 0.1 = 10% of 97%(does not have the disease). So

P(A) = 0.90*0.03 + 0.1*0.97 = 0.124

Intersection of A and B:

Positive test and has the disease, so 90% of 3%

P(A \cap B) = 0.9*0.03 = 0.027

What is the conditional probability that she does, in fact, have the disease

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.027}{0.124} = 0.2177

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

3 0
3 years ago
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