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Scorpion4ik [409]
3 years ago
8

Please help i really need it !!!!

Mathematics
1 answer:
Vika [28.1K]3 years ago
4 0
C, i think you forgot an x
(x+11)+(x-7)
x+11+x-7
x+x+4
2x+4
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The surface area of an oil spill gets 105% larger every day, represented by the function s(x) = (1.05)x − 1. On the first day, i
ioda
The given scenario above is like a geometric sequence with r or common ratio being 1.05 and the first term being 31 square meters. The nth term of the sequence is calculated through the equation,
                        A15 = (A1)(r)^(n - 1)
Substituting,
                        A15 = (31)(1.05)^(15 - 1) = 61.3778 square meter
Therefore, the area covered by the spill after the 15th day is approximately 61.4 square meters. 
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3 years ago
What is slope and intercept
swat32
Basically slope is how steep a straight line is and an intercept is where a line crosses the x-axis and y-axis. It's easier to use it than it is to explain it. In a slope-intercept formula (y= mx+b) m = slope and b= y-intercept. With this info you can solve different problems and graph equations. 
4 0
4 years ago
Find a vector equation and parametric equations for the line. (Use the parameter t.) The line through the point (0, 11, −8) and
NNADVOKAT [17]

Answer:

The vector equation of the line is \overrightarrow {r}=(11j-8k)+t(4i-4j+6k) and parametric equations for the line are x=4t, y=11-4t, z=-8+6t.

Step-by-step explanation:

It is given that the line passes through the point (0,11,-8) and parallel to the line

x=-1+4t

y=6-4t

z=3+6t

The parametric equation are defined as

x=x_1+at,y=y_1+bt,z=z_1+ct

Where, (x₁,y₁,z₁) is point from which line passes through and <a,b,c> is cosine of parallel vector.

From the given parametric equation it is clear that the line passes through the point (-1,6,3) and parallel vector is <4,-4,6>.

The required line is passes through the point (0,11,-8) and parallel vector is <4,-4,6>. So, the parametric equations for the line are

x=4t

y=11-4t

z=-8+6t

Vector equation of a line is

\overrightarrow {r}=\overrightarrow {r_0}+t\overrightarrow {v}

where, \overrightarrow {r_0} is a position vector and \overrightarrow {v} is cosine of parallel vector.

\overrightarrow {r}=(11j-8k)+t(4i-4j+6k)

Therefore the vector equation of the line is \overrightarrow {r}=(11j-8k)+t(4i-4j+6k) and parametric equations for the line are x=4t, y=11-4t, z=-8+6t.

3 0
3 years ago
17 = -47 + 6.98x. solve the equation. round your answer to the nearest hundredth
shutvik [7]
Solving it and nearing it to the hundredth would be 9.169 :)
6 0
3 years ago
Read 2 more answers
Please help asap thanks I only need the answer not an explanation
Doss [256]

Answer:

7.810.

Step-by-step explanation:

that is the answer

3 0
3 years ago
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