Use the diagram that awnser the questions.

Mathematics

1 answer:

nadya68 [22]4 years ago

3 0

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Find Slope for Line m:
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Two points on the graph: (-4. 3) and (0,-4)

$\text {Slope = } \dfrac{3- (-4)}{-4 - 0} = -\dfrac{7}{4}$

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Find Slope for Line n:
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Two points on the graph: (1, 2) and (3, -2)

$\text {Slope = } \dfrac{2 - (-2)}{1-3} = -\dfrac{4}{2} = -2$

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Find Slope for Line k:
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Two points on the graph: ( -3 , -3) (4 , 1)

$\text {Slope = } \dfrac{1 - (-3)}{4 - (-3)} = \dfrac{4}{7}$

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Answer: Since M and N do not have the same slope, they are not parallel.

Answer: The slope of K is the negative reciprocal of M, therefore they are perpendicular.
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For every $3.00 donated to a certain charity by Club A, $1.25 was donated by Club B. If the combined total amount donated to the

shtirl [24]

Answer:

D, $18,000.00

Step-by-step explanation:

Club A

$3 x is donated where x is the number of donations

Club B

$1.25x is donated where x is the number of donations

The total of donations is 25500.00

Add the donations times the dollar amount for Club A and Club B and you get the total amount donated

$3x +$1.25x = 25500.00

Combine like terms

4.25x = 25500.00

Divide by 4.25 on each side

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x =6000

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4 0

3 years ago

Read 2 more answers

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goldenfox [79]

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5 0

4 years ago

Answer numbers 1-4 with work please

aleksley [76]

Answer:

$\large\boxed{Q1.\ 6\dfrac{1}{4}\ cups}\\\boxed{Q2.\ 3\dfrac{1}{3}\ pounds}\\\boxed{Q3.\ 72:64=9:8}\\\boxed{Q4.\ 32:64=12:24}$

Step-by-step explanation:

In Q1 and Q2 we must make the proportion.

$Q1.\\s-\text{number of cups of sugar}\\\\\dfrac{2\frac{1}{2}}{\frac{2}{5}}=\dfrac{s}{1}\to s=2\dfrac{1}{2}:\dfrac{2}{5}=\dfrac{2\cdot2+1}{2}\cdot\dfrac{5}{2}=\dfrac{5}{2}\cdot\dfrac{5}{2}=\dfrac{25}{4}=6\dfrac{1}{4}$

$Q2.\\p-\text{number of pounds of mashed potatoes}\\\\\dfrac{2\frac{4}{6}}{\frac{4}{5}}=\dfrac{p}{1}\to p=2\dfrac{4}{6}:\dfrac{4}{5}=\dfrac{2\cdot6+4}{6}\cdot\dfrac{5}{4}=\dfrac{16\!\!\!\!\!\diagup^4}{6}\cdot\dfrac{5}{4\!\!\!\!\diagup_1}=\dfrac{20}{6}=\dfrac{20:2}{6:2}=\dfrac{10}{3}=3\dfrac{1}{3}$

$Q3.\\\\72:64=\dfrac{72}{64}=\dfrac{72:8}{64:8}=\dfrac{9}{8}=9:8\\\\\text{Other method}\\\\72:64=9:x\to\dfrac{72}{64}=\dfrac{9}{x}\qquad\text{cross multiply}\\\\72x=(64)(9)\qquad\text{divide both sides by 72}\\\\x=\dfrac{576}{72}\\\\x=8$

$Q4.\\\\32:x=12:24\\\\\dfrac{32}{x}=\dfrac{12}{24}\qquad\text{cross multiply}\\\\12x=(32)(24)\qquad\text{divide both sides by 12}\\\\x=\dfrac{768}{12}\\\\x=64$