Critical points is where the derivative (slope) is zero or does not exist. So to do this we have to find the derivative of our function:

So we apply chain rule:
=

Set our first derivative to zero and solve for x:
3(x^2 - 1) * 2x = 0
So we can see that (by plugging in) 0, -1 and 1 makes our solution true
So our critical value is x = 0, x = -1, x = 1
G(x) = 2x² - 5x + 2 = 2x² - 4x - x + 2 = 2x · x - 2x · 2 - 1 · x - 1 · (-2)
= 2x(x - 2) -1(x - 2) = (x - 2)(2x - 1)
g(x) = 0 ⇔ (x - 2)(2x - 1) = 0 ⇔ x - 2 = 0 or 2x - 1 = 0
x = 2 or x = 0.5
Answer:

Step-by-step explanation:
When you have exponents above a like term and they are being multiplied together, you add them.
For example:

So let's group like terms in the numerator:
We can add terms like in the example.

Let's rearrange the denominator.

Now we have:
Cancel like terms
4/8 = 1/2
= 1 So it cancels
= s Since s is raised to the -1 it goes on top and becomes s.

Now we combine everything back together:

Answer:
i dont know
Step-by-step explanation:
sorry big homie on school