Microscopic hair structures that extend far out from animal cells, they are important and play a vital part in both humans and animals develpoment and everday life..i hope this helps..
The carbon 14 left from this animal is 3 grams of 24 grams which is: 3g/24g= 1/8 times of its original mass. Then, the age of the animal fossil would be:
final weight= initial weight * (1/2) ^ time/half-live
1/8 initial weight = initial weight * (1/2) ^ time/half-live
log2 1/8= log2 (1/2) ^ time/half-live
-3= -time/half-live
time= -3 * -(half-live)
time= 3 half-live
If the half-live is 5730 years, the age would be: 3* 5730= 17.190 years.
Answer:
the pathway will be under-expressed.
- the alpha subunit helps to bind with either GDP or GTP. when the α subunit is bound with GDP, it will be bound to β and γ subunits and thus forms an inactive state for G-protein.
- when the alpha subunit binds with the GTP, it becomes activated and dissociates β and γ subunits.
if G-protein Coupled Receptor is unable from dissociating β and γ subunits, then the pathway will go under expression.
The chemical qualities of the alpha subunit allow it to bind easily to one of two guanine subunits, GDP or GTP. The protein thus has two functional formations. When GDP is bound to the alpha subunit, the alpha subunit remains bound to the beta-gamma subunit to form an inactive trimeric protein.
G-proteins, cAMP, and Ion Channel Opening. The alpha subunit activates adenylate cyclase, in purple, and loses GTP. Adenylate cyclase converts ATP to cyclic AMP, which then activates Protein Kinase, shown in blue. Protein Kinase phosphorylates an ion channel, letting sodium ions rush into the cell.
As a result of the ligand binding to its site on the G-protein-linked receptor, A) the G-protein changes conformation and GTP replaces the GDP on the alpha subunit. ... Inactivation of the alpha subunit occurs when its own phosphorylase activity removes a phosphate from the GTP.
Answer:
They deleted it idek why but HAPLOID
Explanation:
