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zvonat [6]
3 years ago
9

Each grade level at Hooperville Schools has 298 students.

Mathematics
1 answer:
madreJ [45]3 years ago
4 0

Answer:

(a) 3,874 students.

(b) 46,488 students.

Step-by-step explanation:

We have been given the each grade level at Hooperville Schools has 298 students.

(a) To find the number of students that attend Hooperville Schools, we will multiply the number of grades by 298.

\text{Students that attend Hooperville Schools}=13\times 298

\text{Students that attend Hooperville Schools}=3,874

Therefore, 3,874 students attend Hooperville Schools.

(b) We have been given that nearby district, Willington, is much larger. They have 12 times as many students.

To find the number of students that attend schools in Willington, we will multiply number of students at Hooperville schools by 12.

\text{Students that attend Willington Schools}=12\times 3,874

\text{Students that attend Willington Schools}=46,488

Therefore, 46,488 students attend schools in Willington.

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3 years ago
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Vedmedyk [2.9K]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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Alex777 [14]

Answer:

<h2>A)t=6.7</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
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<h3>given:</h3>

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<h3>to solve:</h3>

t

<h3>tips and formulas:</h3>
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step - 1 :  \: define

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step - 2 :  \\ divide \: both \: sides \: by \:  - 4

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step - 3 :  \\ solve \: the \: quadratic

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define \: a ,b \: and \: c \\ which \: are \: 1, - 3 \: and \:  - 25 \: respectively

t =  \frac{ - ( - 3)± \sqrt{ {( - 3)}^{2} - 4.1. - 25 }  }{2.1}

t =  \frac{  3± \sqrt{ 9    + 100}  }{2}

t = \frac{3 +  \sqrt{ 109 } }{2}

t =  \frac{3  -  \sqrt{ 109 } }{2}

t = 6.7 \\ t =  - 3.7

as \: we \: know \: time \: cannot \: be \: negative

\huge \therefore \: t = 6.7

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Step-by-step explanation:

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