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Alecsey [184]
3 years ago
10

Anyone know the answer to this

Mathematics
2 answers:
Otrada [13]3 years ago
7 0

Answer:

130m

Step-by-step explanation:

I took the iready and got 100%

uranmaximum [27]3 years ago
6 0

Answer:

130m

120 squared + 50 squared

square root of 16900

130

(meters)

130 meters :)

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What is the value of f(x), if x is -8?
tensa zangetsu [6.8K]

Answer:

-8f

Step-by-step explanation:

you will substitute in the numbers and multiply

Because f is a variable you write the -8 and attach the f to it

8 0
2 years ago
What does 4(m-2)=2(m-9) equal
marshall27 [118]

Answer:

m = -5

Step-by-step explanation:

Simplify both sides of the equation.

4(m−2)=2(m−9)

(4)(m)+(4)(−2)=(2)(m)+(2)(−9)(Distribute)

4m+−8=2m+−18

4m−8=2m−18

Subtract 2m from both sides.

4m−8−2m=2m−18−2m

2m−8=−18

Add 8 to both sides.

2m−8+8=−18+8

2m=−10

Divide both sides by 2.

2m/2 = -10/2

m = -5

3 0
3 years ago
6. Josh has a $250 gift card to Under Armour.
Komok [63]

Answer:

x=10  (22.5x+6.50=250)

Step-by-step explanation:

6 0
2 years ago
Select all the expressions which are equivalent to<br> -4/3p - 2/5
AVprozaik [17]

Answer

-2/5 -4/3 p and -4/3p+ (-2/5)

Step-by-step explanation:

those two are the only answers that has both parts of the expressions as negative.

6 0
3 years ago
A company manager for a tire manufacturer is in charge of making sure there is the least amount of defective tires. If the tire
Anestetic [448]

Answer:

0.347% of the total tires will be rejected as underweight.

Step-by-step explanation:

For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.

And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.

1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344

1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792

The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)

Using data from the normal distribution table

P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight

Hope this Helps!!!

6 0
3 years ago
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