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Flura [38]
3 years ago
10

The ratio to cranberry juice and mango juice is 3:2 they used 4 quarts of cranberry juice last week. This week mindy and her fri

ends want to make 3 times as much punch. How much mango juice do mindy friends need
Mathematics
1 answer:
IrinaVladis [17]3 years ago
8 0

Answer:

The amount of mango juice needed is 8 quarts

Step-by-step explanation:

To calculate the amount of mango juice needed, we will need to know the amount used the previous week.

Cranberry juice to Mango juice is 3:2 with cranberry used being 4 quarts. Let the quarts of Mango juice used be x

This means;

3/2 = 4/x

1.5 = 4/x

1.5x = 4

x = 4/1.5 quarts

Since they are making 3 times as much punch, the amount of mango juice needed will be 4/1.5 * 3 = 4 * 2 = 8 quarts

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344/9=38.222 which you would round to 39 tables
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Which questions are statistical questions?
Yanka [14]

Answer:

Which questions are statistical questions?

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Step-by-step explanation:

Need to include numerical values

8 0
3 years ago
∆ABC is rotated 100° counterclockwise about point P to create ∆A'B'C'. what is angle m C'A'B'?
dolphi86 [110]
The answer would be c, 70

7 0
3 years ago
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A student records the number of hours that they have studied each of the last 23 days. They compute a sample mean of 2.3 hours a
natita [175]

Answer:

the standard deviation increases

Step-by-step explanation:

Let x₁ , x₂, .   .   .  , x₂₃ be the actual data observed by the student

The sample means  = x₁  +  x₂  +  .   .   .  , x₂₃ / 23

= \frac{x_1 +x_2 +...x_2_3}{23}

= 2.3hr

⇒\sum xi =2.3 \times 23 = 52.9hrs

let x₁ , x₂, .   .   .  , x₂₃  arranged in ascending order

Then x₂₃ was 10  and has been changed to 14

i.e x₂₃ increase to 4

Sample mean  = \frac{x_1 +x_2 +...x_2_3}{23}

\frac{52.9hrs + 4}{23} \\\\= \frac{56.9}{23} \\\\= 2.47

therefore, the new sample mean is 2.47

2) For the old data set

the median is x_1_2(th) values

[\frac{n +1}{2} ]^t^h value

when we use the new data set only x₂₃ is changed to 14

i.e the rest all observation remain unchanged

Hence, sample median = [{x_1_2]^t^h value remain unchange

sample median = 2.5hrs

The Standard deviation of old data set is calculated

=\sqrt{\frac{1}{n-1} \sum (xi - \bar x_{old})^2 } \\\\=\sqrt{\frac{1}{22}\sum ( xi - 2.3)^2 }---(1)

The new sample standard sample deviation is calculated as

= \sqrt{\frac{1}{n-1} \sum (xi-2.47)^2} ---(2)

Now, when we compare (1) and (2)  the square distance between each observation xi and old mean is less than the squared distance between each observation xi and the new mean.

Since,

(xi - 2.3)²  ∑ (xi - 2.47)²

Therefore , the standard deviation increases

6 0
3 years ago
Rewrite the expressions by using the distributive property and collecting like terms. 1/6(12s + 6)
Citrus2011 [14]

For the distributive property, multiply the number outside the parentheses by each term inside the parentheses.

1/6 x 12s = 2s

1/6 x 6 = 1

Now combine them to get the final answer: 2s + 1

4 0
2 years ago
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