NEED HELP!! #2-9 or what ever questions u wanna do please in need of help!

Mathematics

1 answer:

kykrilka [37]2 years ago

8 0

6. X=8cm
This is because the length on the smaller triangle(4cm) needs to be doubled to fit the length of larger triangle,which will be 8cm (4 x 2 = 8)

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1 Select the correct answer. Kalid simplified a polynomial expression as shown. (6x3 + 8x2 − 7x) − (2x2 + 3)(x − 8) step 1 (6x3

Eva8 [605]

Answer:

So, the step1 is correct.

Step-by-step explanation:

The expression is

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So, the step 1 is correct.

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A dog chases a squirrel. The dog is originally 200 feet away from the squirrel. The dog's speed is 150 feet per minute. The squi

Dafna11 [192]

Answer:

15 seconds

Step-by-step explanation:

If you make a table of values for the dog and the squirrel using d = rt, then the rates are easy: the dog's rate is 150 and the squirrel's is 100. The t is what we are looking for, so that's our unknown, and the distance is a bit tricky, but let's look at what we know: the dog is 200 feet behind the squirrel, so when the dog catches up to the squirrel, he has run some distance d plus the 200 feet to catch up. Since we don't know what d is, we will just call it d! Now it seems as though we have 2 unknowns which is a problem. However, if we solve both equations (the one for the dog and the one for the squirrel) for t, we can set them equal to each other. Here's the dog's equation:

d = rt

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And the squirrel's:

d = 100t

If we solve both for t and set them equal to each other we have:

$\frac{150}{d+200} =\frac{100}{d}$

Now we can cross multiply to solve for d:

150d = 100d + 20,000 and

50d = 20,000

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But we're not looking for the distance the squirrel traveled before the dog caught it, we are looking for how long it took. So sub that d value back into one of the equations we have solved for t and do the math:

$t=\frac{100}{d}=\frac{100}{400} =\frac{1}{4}$