Answer:
zero ( 0) times.
Explanation:
In the code;
i = 2
while ( i > 2){
i = floor( i/2 );
z = z + 1;
}
the variable " i " is assigned the integer " 2 ", then the while statement loops with a condition of a greater " i " value and divides the value by two for every loop.
But in this case, the while statement is not executed as the value of " i " which is 2 is not greater than but equal to two.
If 29 bits of the 32 available addressing bits are used for the subnet, then only 3 bits giving 2^3=8 combinations remain for the host addresses.
In reality, the all zeros and all ones addresses are reserved. So, 8 addresses can exist, but 6 of those are available.
The way the question is formulated it seems the answer 8 is what they're after.
Answer:
Float circumference; // Create a float variable
Explanation:
The float datatype is used for storing the decimal point values .The syntax to declaring any float variable is given below.
float variable-name;
float circumference; // create a float variable
circumference=89.9007;; // store the value in circumference
Following are program in c++
#include <iostream> // header file
using namespace std; //namespace
int main() // main function
{
float circumference; // creating variable float
circumference=89.9007; // storing value
cout<<circumference; // display value circumference
return 0;
}
Output:
89.9007
Answer:
Please see the attached image
Explanation:
<span>import java.util.Scanner;
public class PrintWithComma {
public static void main (String [] args) {
final int NUM_VALS = 4;
int[] hourlyTemp = new int[NUM_VALS];
int i = 0;
hourlyTemp[0] = 90;
hourlyTemp[1] = 92;
hourlyTemp[2] = 94;
hourlyTemp[3] = 95;
/* Answer */
System.out.println("");
return;
}
}</span>
