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DENIUS [597]
2 years ago
14

How to write a C++ program that allows a user to enter their rating of the three movies in the Dark Knight Trilogy and then disp

lay each rating entered, the highest rating, the lowest rating, and the average of the ratings??
Computers and Technology
1 answer:
8_murik_8 [283]2 years ago
8 0

The program is an illustration of arrays.

Arrays are used to hold multiple values in one variable.

The program in C++ where comments are used to explain each line is as follows:

#include <iostream>

using namespace std;

int main(){

   //This declares an array of three elements for the three ratings

   int ratings[3];

   //This initializes the sum of the ratings to 0

   int total = 0;

   //The following iteration gets input for the three ratings

   for(int i = 0; i<3;i++){

       cin>>ratings[i];

       //This calculates the sum of all inputs

       total+=ratings[i];

   }

   //This declares and initializes the lowest and the highest ratings

   int lowest = ratings[0], highest = ratings[0];

   //This iterates through the array

   for(int i = 1; i<3;i++){

       //The following if condition determines the lowest rating

       if (lowest > ratings[i]){    lowest = ratings[i];        }

       //The following if condition determines the highest rating

       if (highest < ratings[i]){            highest = ratings[i];        }

   }

   //This prints the output header

   cout<<"The ratings are: ";

   //The following iteration prints the three ratings

   for(int i = 0; i<3;i++){

       cout<<ratings[i]<<" ";   }

   //The prints the highest ratings

cout<<endl<<"Highest: "<<highest<<endl;

   //The prints the lowest rating

   cout<<"Lowest: "<<lowest<<endl;

   //The prints the average rating

cout<<"Average: "<<total/3<<endl;

   return 0;

}

At the end of the program, the ratings entered, the highest rating, the lowest rating, and the average of the ratings are printed.

See attachment for sample run

Read more about similar programs at:

brainly.com/question/13261254

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Write a C program that reads two hexadecimal values from the keyboard and then stores the two values into two variables of type
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Solution :

#include  $$

#include $$

#include $$

//Converts $\text{hex string}$ to binary string.

$\text{char}$ * hexadecimal$\text{To}$Binary(char* hexdec)

{

 

long $\text{int i}$ = 0;

char *string = $(\text{char}^ *) \ \text{malloc}$(sizeof(char) * 9);

while (hexdec[i]) {

//Simply assign binary string for each hex char.

switch (hexdec[i]) {

$\text{case '0'}:$

strcat(string, "0000");

break;

$\text{case '1'}:$

strcat(string, "0001");

break;

$\text{case '2'}:$

strcat(string, "0010");

break;

$\text{case '3'}:$

strcat(string, "0011");

break;

$\text{case '4'}:$

strcat(string, "0100");

break;

$\text{case '5'}:$

strcat(string, "0101");

break;

$\text{case '6'}:$

strcat(string, "0110");

break;

$\text{case '7'}:$

strcat(string, "0111");

break;

$\text{case '8'}:$

strcat(string, "1000");

break;

$\text{case '9'}:$

strcat(string, "1001");

break;

case 'A':

case 'a':

strcat(string, "1010");

break;

case 'B':

case 'b':

strcat(string, "1011");

break;

case 'C':

case 'c':

strcat(string, "1100");

break;

case 'D':

case 'd':

strcat(string, "1101");

break;

case 'E':

case 'e':

strcat(string, "1110");

break;

case 'F':

case 'f':

strcat(string, "1111");

break;

default:

printf("\nInvalid hexadecimal digit %c",

hexdec[i]);

string="-1" ;

}

i++;

}

return string;

}

 

int main()

{ //Take 2 strings

char *str1 =hexadecimalToBinary("FA") ;

char *str2 =hexadecimalToBinary("12") ;

//Input 2 numbers p and n.

int p,n;

scanf("%d",&p);

scanf("%d",&n);

//keep j as length of str2

int j=strlen(str2),i;

//Now replace n digits after p of str1

for(i=0;i<n;i++){

str1[p+i]=str2[j-1-i];

}

//Now, i have used c library strtol

long ans = strtol(str1, NULL, 2);

//print result.

printf("%lx",ans);

return 0;

}

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Answer:

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Explanation:

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