Question

One number is 6 more than another. Their product is -9. Need help fast

Answer 1

Answer: the numbers are 3 and -3

Step-by-step explanation:

let the unknown number be x

The first UNKNOWN NUMBER = X

The second unknown number is = 6 + x

Their product = -9

(X)(6 + X) = -9

6x +$x^{2}$=-9

$x^{2}$ +6x +9=0

we multiply the coefficient of x which is 1 with 9

now, we look for two numbers that when multiplied will give us 9 and when added will give 6 and that is 3 and 3

$x^{2}$ +3x+3x +9 = 0

x(x+3) +3(x+3) = 0

(x +3 ) = 0

or (x +3)=0

x +3 =0

x=0 -3

x =-3

x +3=0

x =0-3

x =-3

since the numbers are the same ,we pick one

therefore,the first number =x =-3

the second number is 6 + x=6 + (-3)

6-3=3