Answer:
the greatest common factor is 6
First right equals brainliest, Pls dont answer for the points this is serious. I just need this and 3 more which I will ask late
r. Anyway I am making this worth more points because I need help:)
2 answers:
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Answers & Step-by-step explanation:
<h2>PEMDAS (Parenthesis, exponents, multiplication, division, addition, subtraction)</h2>Now let's solve your problems!
<h2>___________________________________________________</h2><h2>16.</h2>First, we see if there are any parentheses. Since there are no parentheses, we will evaluate the exponent 3² first.
After this, our problem now looks like this:
<h2>Next, since multiplication (not subtraction) is next on the list, we will evaluate 6 × 3, which equals 18.
After that, we will subtract:
41 - 9 = 32
18 - 26 = -8
We now have 32/-8 or 4/-1 or simply -4.
<h2>The answer is: -4</h2><h2>___________________________________________________</h2><h2>17.</h2>With this, one, note the parentheses. This means that we will do these operations first.
(21 - 4²) = 5
(3 + 1) = 4
The problem now looks like this:
Next, we do the exponents:
8² = 64
After that, we do the multiplication of 5 x 4, which equals 20.
We now have 20/64 - 44, which simplifies to 20/20 or 1/1 or 1.
<h2>The answer is: 1</h2><h2>___________________________________________________</h2><h2>18.</h2>Again, we see parentheses, so that means we need to do these operations first.
(6² - 20) = 16
We now have:
48 ÷ 16 + 5
48/16 = 3 and 3 + 5 = 8
<h2>The answer is: 8</h2><h2>___________________________________________________</h2><h2>19.</h2>Here, we see an exponent 3³, so we'll need to evaluate this first.
3³ = 27
We now have:
4 × 27 ÷ 18 + 14
4 × 27 = 108
108/18 = 6
And finally:
6 + 14 = 20
<h2>The answer is: 20</h2><h2>___________________________________________________</h2><h2>20.</h2>Here we again see the parentheses, which means we need to evaluate the subtraction first.
3 - 8 = -5
We now have:
11 + 2 (-5)
2 × -5 = -10
11 + -10 (same as 11 - 10) = 1
<h2>The answer is: 1</h2><h2>___________________________________________________</h2><h2><em>I AM ALWAYS HAPPY TO HELP :)</em></h2>
These tables have infinitely many values, but the simplest ones would be:
a) x|y
3|5
6|10
9|15
b) x|y
2|1
4|2
6|3
Your graph for c would look like the attached picture
a) x|y
3|5
6|10
9|15
b) x|y
2|1
4|2
6|3
Your graph for c would look like the attached picture