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pentagon [3]
3 years ago
8

What is the value of Y when x=3 if the equation of the regression line is y=3.8X+ 23.1

Mathematics
1 answer:
Anna [14]3 years ago
4 0

Answer:

y = 34.5

Step-by-step explanation:

<u>Step 1:  Set x to 3</u>

<u />y = 3.8x + 23.1

y = 3.8(3) + 23.1

y = 11.4 + 23.1

y = 34.5

Answer:  y = 34.5

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dimulka [17.4K]

Answer:

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8 0
3 years ago
I need help plis <br> thanks
julia-pushkina [17]

Answer:

y = -3x - 1

Step-by-step explanation:

Let he equation of the line is,

y = mx + b

Here, m = slope of the line

b = y-intercept

Slope 'm' of the line passing through two points (x_1,y_1) and (x_2,y_2) is,

m = \frac{y_2-y_1}{x_2-x_1}

Slope of the line passing through (-2, 5) and (2, -7) will be,

m = \frac{-7-5}{2+2}

m = -3

Equation of the line will be,

y = -3x + b

Since, this line passes through (-2, 5),

5 = -3(-2) + b

5 = 6 + b

b = 5 - 6

b = -1

Therefore, equation of the line will be,

y = -3x - 1

6 0
3 years ago
Please help me out with this ill mark as brainiest
dem82 [27]

Answer:

500,000

250,000

125000

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Equation : 1000000 / n^2

Step-by-step explanation:

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8 0
3 years ago
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Find the square roots of 9604​
OLEGan [10]

Answer:

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You have to use prime factor decompisition. I hope this helps

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Bezzdna [24]

Answer:

3.5 is the correct answer

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3 years ago
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