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Mamont248 [21]
3 years ago
10

HELPPSOJSUSHHWYAYSYYSYYEHWHWHS​

Mathematics
1 answer:
OlgaM077 [116]3 years ago
4 0

Answer:

1. (-4, 1)

2. I substituted (y = x + 5) into (3x + y = -11) first before substituting the value of x into (y = x + 5) to find the value of y.

Step-by-step explanation:

Substitute y = x + 5 into 3x + y = -11:

3x + y = -11

3x + x + 5 = -11

4x + 5 = -11

4x = -11 - 5

    = -16

x = -16 ÷ 4

x = -4

Substitute x = 4 into y = x + 5:

y = x + 5

y = -4 + 5

y = 1

A coordinate point is written like this: (x, y)

Thus, the final answer is: (-4, 1)

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5 0
3 years ago
Life tests on a helicopter rotor bearing give a population mean value of 2500 hours and a population standard deviation of 135 h
stira [4]

Answer:

The percent of the parts are expected to fail before the 2100 hours is 0.15.

Step-by-step explanation:

Given :Life tests on a helicopter rotor bearing give a population mean value of 2500 hours and a population standard deviation of 135 hours.

To Find : If the specification requires that the bearing lasts at least 2100 hours, what percent of the parts are expected to fail before the 2100 hours?.

Solution:

We will use z score formula

z=\frac{x-\mu}{\sigma}

Mean value = \mu = 2500

Standard deviation = \sigma = 135

We are supposed to find  If the specification requires that the bearing lasts at least 2100 hours, what percent of the parts are expected to fail before the 2100 hours?

So we are supposed to find P(z<2100)

so, x = 2100

Substitute the values in the formula

z=\frac{2100-2500}{135}

z=−2.96

Now to find P(z<2100) we will use z table

At z = −2.96 the value is 0.0015

So, In percent = .0015 \times 100=0.15\%

Hence The percent of the parts are expected to fail before the 2100 hours is 0.15.

5 0
3 years ago
State the number of possibilities: you select 4 people to represent your class of 205 students
balu736 [363]
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6 0
3 years ago
The indicated function y1(x) is a solution of the given differential equation. Use reduction of order or formula (5) in Section
lisabon 2012 [21]

Answer:

\therefore y_2(x)=-\frac{e^{-6x}}{8}

The general solution is

y=c_1e^{2x}-c_2.\frac{e^{-6x}}{8}

Step-by-step explanation:

Given differential equation is

y''-4y'+4y=0

and y_1(x)=e^{2x}

To find the y_2(x) we are applying the following formula,

y_2(x)=y_1(x)\int \frac{e^{-\int P(x) dx}}{y_1^2(x)} \ dx

The general form of equation is

y''+P(x)y'+Q(x)y=0

Comparing the general form of the differential equation to the given differential equation,

So, P(x)= - 4

\therefore y_2(x)=e^{2x}\int \frac{e^{-\int 4dx}}{(e^{2x})^2}dx

           =e^{2x}\int \frac{e^{-4x}}{e^{4x}}dx

           =e^{2x}\int e^{-4x-4x} \ dx

            =e^{2x}\int e^{-8x} \ dx

            =e^{2x}. \frac{e^{-8x}}{-8}

           =-\frac{e^{-6x}}{8}

\therefore y_2(x)=-\frac{e^{-6x}}{8}

The general solution is

y=c_1e^{2x}-c_2.\frac{e^{-6x}}{8}

4 0
3 years ago
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