Simple 38487283847482828910101010101010010294587585858584839395848
Answer:
I got 1
Step-by-step explanation:
cos A/cos B
(3/4.24) / (3/4.24)
Since anything over itself is 1, the answer is 1
Hope this helps ;)
Answer:
The percent of the parts are expected to fail before the 2100 hours is 0.15.
Step-by-step explanation:
Given :Life tests on a helicopter rotor bearing give a population mean value of 2500 hours and a population standard deviation of 135 hours.
To Find : If the specification requires that the bearing lasts at least 2100 hours, what percent of the parts are expected to fail before the 2100 hours?.
Solution:
We will use z score formula

Mean value = 
Standard deviation = 
We are supposed to find If the specification requires that the bearing lasts at least 2100 hours, what percent of the parts are expected to fail before the 2100 hours?
So we are supposed to find P(z<2100)
so, x = 2100
Substitute the values in the formula


Now to find P(z<2100) we will use z table
At z = −2.96 the value is 0.0015
So, In percent = 
Hence The percent of the parts are expected to fail before the 2100 hours is 0.15.
If you have 205 students, and only 4 open positions, there would be multiple possibilities. For this question I would multiply 4 by 205, in which would contain every single possibility. 4 positions, 205 students, 4 times 205 would be 820 possibilities. Hope this helps.
Answer:

The general solution is

Step-by-step explanation:
Given differential equation is
y''-4y'+4y=0
and 
To find the
we are applying the following formula,

The general form of equation is
y''+P(x)y'+Q(x)y=0
Comparing the general form of the differential equation to the given differential equation,
So, P(x)= - 4







The general solution is
