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Answer:
The smaller bottle holds 12.5 ml of perfume.
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<h2>Given</h2>- Two bottles of similar shape;
- Larger bottle has volume of 100 ml;
- The length of larger bottle is 10 cm;
- The length of smaller bottle is 5 cm.
- The volume of smaller bottle.
Find the scale factor, the ratio of corresponding dimensions:
We know the volume is the function of three dimensions, therefore the ratio of volumes is the cube of the scale factor:
Substitute the known values and find the volume of small bottle:
The smaller bottle holds 12.5 ml of perfume.
Answer:
6m
Step-by-step explanation:
the side of first square = 3 m
area of first square = 3^2= 9 m^2
let the side of second square = x m
since diagonal of first square = x m as per the question
in a square each angle is 90 degree
therefore by applying pythagorus theorem ,
diagonal ^2 = side^2 + side ^2
diagonal^2 = 3^2+3^2=9+9
DIAGONAL= square root of 18
diagonal= 3 m = side of second square
therefore in second square ,
one angle is 90 degree , therefore by applying pythagorue theorem
diaqonal^2 = side ^2 + side ^2 = (3)^2 + ( 3
)^2
diagonal ^2 = 18 + 18
diagonal = square root of 36
therefore diagonal of second square is 6m
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