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Olin [163]
3 years ago
10

4. M(7, 3) is the midpoint of RS. The coordinates of point S are (8,4). What are the

Mathematics
1 answer:
seraphim [82]3 years ago
7 0

The co-ordinates of point R is (6 , 2)

<h3><u>Solution:</u></h3>

Given that M(7, 3) is the midpoint of RS

Also co-ordinates of point S is (8, 4)

<em><u>To find: co-ordinates of point R</u></em>

The midpoint of two points P(x_1, y_1) and Q(x_2, y_2) is given as:

M=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

Here midpoint M = (7, 3) and point S (x_1 , y_1) = (8, 4)

Point R = (x_2, y_2)

Substituting the values in formula we get,

(7,3)=\left(\frac{8+x_{2}}{2}, \frac{4+y_{2}}{2}\right)

Comparing both the sides we get,

\frac{8+x_{2}}{2}=7 and \frac{4+y_{2}}{2}=3

On solving,

\begin{array}{l}{14=8+x_{2}} \\\\ {x_{2}=6}\end{array}

Also,

\begin{array}{l}{4+y_{2}=6} \\\\ {y_{2}=2}\end{array}

Thus the co-ordinates of point R is (6 , 2)

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Aneli [31]

Answer:

The required equation is x=\frac{-(-9)\pm \sqrt{(-9)^2-4(1)(-20)}}{2(1)}.

Step-by-step explanation:

If a quadratic equation is ax^2+bx+c=0, then the quadratic formula is

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

The given quadratic equation is

x^2-9x-20=0

Here, a=1, b=-9 and c=-20.

Substitute a=1, b=-9 and c=-20 in the above quadratic formula.

x=\frac{-(-9)\pm \sqrt{(-9)^2-4(1)(-20)}}{2(1)}

Therefore the required equation is x=\frac{-(-9)\pm \sqrt{(-9)^2-4(1)(-20)}}{2(1)}.

6 0
3 years ago
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Consider the function below
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X-intercept (5,0),(1,0)

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Find the surface area.
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Answer:

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PQRS is a parallelogram. Find the values of a and b. Solve for the value of c if c = a + b.
Alecsey [184]

Answer:

a = 7

b = 7

c = 14             [Correct option is B. 14]

Step-by-step explanation:

Since the shape is a parallelogram, to solve this problem, use some of the properties of a parallelogram:

(i) Opposite sides are parallel and congruent. Being congruent means the sides are identical. In other words, they have the same length.

From the diagram, this means that sides PQ and SR are identical. i.e

=> PQ = SR

=> 6a + 10 = 8a - 4          [collect like terms and solve]

=> 14 = 2a

=> a = 7

(ii) Opposite angles are congruent. Angles PQR and PSR are identical. i.e

<PQR = <PSR = (9b + 2)°

Also,

<SPQ = <SRQ = (18b - 11)°

(iii) Consecutive angles are supplementary. The sum of any two angles that are not opposite to each other is 180°. i.e.

<SPQ + <PQR = 180°

<PQR + <QRS = 180°

<QRS + <RSP = 180°

.

.

.

Also,

<PSR + <SPQ = 180°      

(9b + 2)° + (18b - 11)° = 180°        [expand bracket and solve for b]

9b  + 2 + 18b - 11 = 180

27b - 9 = 180

27b = 189

b = 7

Now, since a = 7 and b = 7;

c = a + b = 7 + 7 = 14

Therefore;

a = 7

b = 7

c = 14

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Step-by-step explanation:

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