8 is the largest possible value of the median of all nine numbers in this list.
Lets simplify it,
⇒ The given six numbers are 7,8,3,5,9 and 5.
⇒ Arrange the six numbers in order 3,5,5,7,8,9.
⇒ We have three more numbers to insert into the list, and the median will be the highest 5(and 5 lowest) number on the list. If the three numbers are greater than 9, the median will be the highest it can possible be.
∴ The median is the 5th item of data which is 8.
∴ Median=8
Hence 8 is the largest possible value of the median of all nine numbers in this list.
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1. Collect like terms.
(6g^2+2g^2-3g^2)+(6-2)+(-4g+5g+2g)
2. Simplify
5g^2+4+3g
Sorry i'm hoping that helps, i'm on a school computer i cant see the picture you attached but i did 6g^2 + 6 - 4g + 2g^2 - 3g^2 + 5g + 2g - 2 because that's what it seemed you were asking.
Answer:
N = 52 * (9/7)^(t/1.5)
Step-by-step explanation:
This problem can be modelated as an exponencial problem, using the formula:
N = Po * (1+r)^(t/1.5)
Where P is the final value, Po is the inicial value, r is the rate and t is the amount of time.
In our case, we have that N is the final number of branches after t years, Po = 52 branches, r = 2/7 and t is the number of years since the beginning (in the formula we divide by 1.5 because the rate is defined for 1.5 years)
Then, we have that:
N = 52 * (1 + 2/7)^(t/1.5)
N = 52 * (9/7)^(t/1.5)
100 miles ............... 2 hours
x miles ................1 hour
x = 100 m / 2 h = 50 m / h