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3 years ago

Find an equation of the plane through the point (3,0,3) which is parallel to the plane 3y−4x−2z=7

1 answer:

5 0

<span>The normal vector for the plane is < 3, -4, -6 >. The general equation of a plane is:<span>oror3( x + 1 ) - 4( y - 3 ) - 6(z + 8 ) = 0
or3x - 4y - 6z = 33</span></span>

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Check all that apply. If csc0=13/5, then:

Galina-37 [17]

I hope this helps you

8 0

3 years ago

Read 2 more answers

47. Which of the following represents 0.2% of 1/5?

erica [24]

First think of what 0.2% is as a fraction,

$0.2\%=\frac{0.2}{100}=\frac{2\cdot10^{-1}}{10^2}=\frac{2}{10^3}=\frac{2}{1000}$

Now multiply the fraction by a fifth,

$\frac{2}{1000}\cdot\frac{1}{5}=\frac{2}{5000}$

Which then simplifies to,

$\frac{2}{5000}=\boxed{\frac{1}{2500}}$

Hope this helps :)

8 0

3 years ago

I need helpppppp i have no idea what im looking at lol

Y_Kistochka [10]

The correct answer is option B which is $SinA = \dfrac{4}{5}$ , $tanA = \dfrac{4}{3}$ , $SecA=\dfrac{5}{3}$ ,

$CosA=\dfrac{3}{5}$ , $CotA=\dfrac{3}{4}$ and $CscA=\dfrac{5}{4}$ .

<h3>What is trigonometry?</h3>

Trigonometry is the branch of mathematics which set up a relationship between the sides and angle of the right-angle triangles.

From the figure we can see that two sides are Ab = 15 cm and BC = 12 cm third side will be calculated by pythagorean theorem.

AC² = AB² - BC²

AC² = 15² - 12²

AC² = 81

AC = √81

AC = 9 cm

Now all the trigonometry identities are:-

$SinA =\dfrac{BC}{AB}=\dfrac{12}{15}= \dfrac{4}{5}$ ,

$tanA =\dfrac{BC}{AC}=\dfrac{12}{9}= \dfrac{4}{3}$ ,

$SecA=\dfrac{AB}{AC}=\dfrac{15}{9}= \dfrac{5}{3}$ ,

$CosA=\dfrac{AC}{AB}=\dfrac{9}{15}= \dfrac{3}{5}$ ,

$CotA=\dfrac{AC}{BC}=\dfrac{9}{12}=}\dfrac{3}{4}$

$CscA=\dfrac{AB}{BC}=\dfrac{15}{12}= \dfrac{5}{4}$ .

Therefore correct answer is option B which is $SinA = \dfrac{4}{5}$ , $tanA = \dfrac{4}{3}$ , $SecA=\dfrac{5}{3}$ , $CosA=\dfrac{3}{5}$ , $CotA=\dfrac{3}{4}$ and $CscA=\dfrac{5}{4}$ .

To know more about Trigonometry follow

brainly.com/question/24349828

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