Question

What is the sum of the interior angles of the polygon shown below

Answer 1

the sum of interior angle of the given polygon be give by the following formula:-

n-1×90 (where n is the no. of side of polygon)

there are 10 side in the given polygon.

on putting the value of n in the formula, we get :-

sum of interior angle is =10-1×90

sum of interior angle is =9×90

sum of interior angle is = 810 degree.

Answer 2

Answer:

$1440^{\circ}$

Step-by-step explanation:

Given : a polygon

To find : Sum of the measures of the interior angles of a polygon with n number of sides

A polygon is a two dimensional formed with straight lines.

For example: triangle, quadrilateral , hexagon etc.

Sum of the measures of the interior angles of a polygon with n number of sides = $\left ( n-2 \right )180^{\circ}$

Number of sides in a given polygon = 10

So, put n = 10 in $\left ( n-2 \right )180^{\circ}$ .

Therefore, sum of the measures of the interior angles of a polygon = $\left ( 10-2 \right )180^{\circ}=8\times 180^{\circ}=1440^{\circ}$