Answer:
Step-by-step explanation:
If the engine torque y (in foot-pounds) of one model of car is given by y=−3.75x^2+23.2x+38.8
The engine speed is at maximum if dy/dx = 0
dy/dx = -2(3.75)x+23.2
dy/dx = -7.5x + 23.2
since dy/dx = 0
0 = -7.5x + 23.2
7.5x = 23.2
x = 23.2/7.5
x = 3.093
Hence the maximum torque is 3.09 rev/min
Step-by-step explanation:
the explanaition of the answer and solution is in the picture, check it out. this is for question 14
Answer:

Step-by-step explanation:
Given that,
A sequence 352,345,338.
First term = 352
Common difference = 345-352 = -7
We need to find the 37th term of the sequence.
The nth term of an AP is given by :

So, the 37th term of the sequence is 100.
Answer:
44
Step-by-step explanation:
gradpoint
Constants are 4,3. The coefficient is 4.