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Blizzard [7]
3 years ago
13

Solve x2 – 8x + 15 < 0. Select the critical points for the inequality shown. –15 –5 –3 3 5

Mathematics
2 answers:
tangare [24]3 years ago
7 0

Answer:

3 and 5

Step-by-step explanation:

Just took it. Edg 2020. Hope this helps :)

svetlana [45]3 years ago
6 0

Answer:

x<3,x<5

Step-by-step explanation:

This an inequality question

x^2-8x+15<0

To solve this question we will have to factorise

x^2-3x-5x+15<0

x(x-3)-5(x-3)

(x-5)(x-3)<0

x-5<0

Add 5 to both sides

x<5

x-3<0

Add 3 to both sides

x<3

Therefore x<3,x<5

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Need help ASAP.<br> 50×50+60-105=?
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Answer:

2,455

Step-by-step explanation:

Use PEMDAS to solve

First multiply 50x50, which is 2,500

50 x 50 + 60 - 105   becomes

2,500 + 60 - 105

Now to the addition or subtraction from left to right

2,560 - 105

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FromTheMoon [43]
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Here, we use                   A = 3.14*r^2.

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3 years ago
A random sample of 15 employees was selected. The average age in the sample was 31 years with a variance of 49 years. Assuming a
vova2212 [387]

Answer:

Assuming ages are normally distributed, the 98% confidence interval for the population average age is [26.3, 35.7].

Step-by-step explanation:

We have to construct a 98% confidence interval for the mean.

The information we have is:

- Sample mean: 31

- Variance: 49

- Sample size: 15

- The age is normally distributed.

We know that the degrees of freedom are

k=n-1=15-1=14

Then, the t-value for a 98% CI is t=2.625 (according to the t-table).

The standard deviation can be estimated from the variance as:

s=\sqrt {s^2}=\sqrt{49}=7

The margin of error is:

E=t_{14}*s/\sqrt{n}\\\\E=2.625*7/\sqrt{15}=18.375/3.873=4.7

Then, the CI can be constructed as:

M-t*s/\sqrt{n}\leq\mu\leq M+t*s/\sqrt{n}\\\\31-4.7\leq \mu \leq 31+4.7\\\\26.3\leq \mu \leq 35.7

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