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3 years ago

Until 2014, the mass of a kilogram was defined as exactly equal to the mass of a special

Mathematics

1 answer:

emmainna [20.7K]3 years ago

7 0

Step-by-step explanation:

We have,

Diameter of cylinder, d = 39.2 mm

Radius, r = 19.6 cm

Height of the cylinder, h = 39.2 mm

It is required to find the surface area of this cylinder. The formula of the surface area of cylinder is given by :

$S=2\pi rh+2\pi r^2\\\\S=2\pi r(h+r)$

Putting all values we get :

$S=2\times\dfrac{22}{7}\times19.6\cdot(39.2+19.6)\\\\S=7244.16\ mm^2$

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The angle \theta_1θ 1 theta, start subscript, 1, end subscript is located in Quadrant \text{III}IIIstart text, I, I, I, end te

Vlad1618 [11]

So the answer is 4 I’m right u wrong ok I’m tell the truth trust me I got 5 hearts this morning

8 0

1 year ago

if you have budgeted 12% of your monthly income for groceries how much can you spend on groceries if you earn 950 bi-weekly

Leviafan [203]

Answer:

$247

Step-by-step explanation:

It depends.

Most months, you will earn $1900, so your budget will be ...

... 12% × $1900 = $228.

In one month out of 6, you will earn $2850, so your budget can be ...

... 12% × $2850 = $342.

_____

If you average out your earnings over 6 months, and compute your budget on that basis, then your monthly grocery budget is ...

... ($950 × 13)/6 × 12% = $247

7 0

2 years ago

Solve the equation and enter the value of x below.<br> x + 29 = 49<br> X =

andrew-mc [135]

Answer:

x = 20

Step-by-step explanation:

x + 29 = 49

- 29 - 29

x=20

5 0

2 years ago

let t : r2 →r2 be the linear transformation that reflects vectors over the y−axis. a) geometrically (that is without computing a

tangare [24]

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b) two eigen values of 'k' = 1, -1

for k = 1, eigen vector is $\left[\begin{array}{c}0\\1\end{array}\right]$

for k = -1 eigen vector is $\left[\begin{array}{c}1\\0\end{array}\right]$

See the figure for the graph:

(a) for any (x, y) ∈ R² the reflection of (x, y) over the y - axis is ( -x, y )

∴ x → -x hence '-1' is the eigen value.

∴ y → y hence '1' is the eigen value.

also, ( 1, 0 ) → -1 ( 1, 0 ) so ( 1, 0 ) is the eigen vector for '-1'.

( 0, 1 ) → 1 ( 0, 1 ) so ( 0, 1 ) is the eigen vector for '1'.

(b) ∵ T(x, y) = (-x, y)

T(x) = -x = (-1)(x) + 0(y)

T(y) = y = 0(x) + 1(y)

Matrix Representation of $T = \left[\begin{array}{cc}-1&0\\0&1\end{array}\right]$

now, eigen value of 'T'

$T - kI = \left[\begin{array}{cc}-1-k&0\\0&1-k\end{array}\right]$

after solving the determinant,

we get two eigen values of 'k' = 1, -1

for k = 1, eigen vector is $\left[\begin{array}{c}0\\1\end{array}\right]$

for k = -1 eigen vector is $\left[\begin{array}{c}1\\0\end{array}\right]$

Hence,

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b) two eigen values of 'k' = 1, -1

for k = 1, eigen vector is $\left[\begin{array}{c}0\\1\end{array}\right]$

for k = -1 eigen vector is $\left[\begin{array}{c}1\\0\end{array}\right]$

Learn more about " Matrix and Eigen Values, Vector " from here: brainly.com/question/13050052

#SPJ4

6 0

11 months ago

Find the distance between (2.3) and (0,6).

Ann [662]

Use the distance formula
And just plug in your numbers and solve

5 0

2 years ago