Answer:
It gives a new string
Explanation:
In programming; when two or more strings are concatenated by a concatenating operator, the result is always a new string.
From the question, we have that
str1 = "Good
str2 = "Evening"
Let's assume that + is the concatenating operator;
str1 + str2 = "Good" + "Evening" = "GoodEvening"
The result of concatenating str1 and str2 is a new string "GoodEvening" while str1 and str2 still maintain their original string value of "Good" and "Evening"
Answer:
Explanation:
One group of students did an experiment to study the movement of ocean water. The steps of the experiment are listed below.
Fill a rectangular baking glass dish with water.
Place a plastic bag with ice in the water near the left edge of the dish.
Place a lighted lamp near the left edge of the dish so that its light falls directly on the plastic bag.
Put a few drops of ink in the water.
The student did not observe any circulation of ink in the water as expected because the experiment had a flaw. Which of these statements best describes the flaw in the experiment? (2 points)
Not enough ink was added.
Not enough water was taken.
The dish was too small for the experiment.
The lamp and the ice bag were at the same place.
Answer:
D. return str.substring(0, 1) + removeDupChars(str.substring(1));
Explanation:
The logic here is following:
If the there are consecutive duplicate characters, return the removeDupChars method. The parameter of the removeDupChars method is a string, but the duplicate of the first character is removed from the string. The else-if part of the program does this job.
If the consecutive characters are not duplicated, return the first character of the string and the removeDupChars method. The parameter of the removeDupChars method is the rest of the string characters. The else part of the program does this job.
When the length of the str becomes one (or when the str is null), the program reaches its base and returns the str. The if part of the program does this job.
C. Combine Documents
---------------------------------
The Combine Documents dialog box lets you specify which files are to be merged.
Answer:
4000k-ohm to 10,000k-ohm
Explanation:
As we know that time constant for an RC circuit is t=RC
Putting the values of t we can get the range of varaiable resistor as;
t=RC
Putting t=2 we get the first value of the range for the variable resistor
2=R*0.500*10^-6
R=2/(0.500*10^-6)
R=4*10^6
R=4000k-ohm
Now putting t=5 we get the final value for the range of variable resistor
t=RC
5=R*0.500*10^-6
R=5/(0.500*10^-6)
R=10*10^6
R=10,000k-ohm
So variable resistance must be made to vary in the range from 4000k-ohm to 10,000k-ohm