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Verdich [7]
3 years ago
6

What is a fire wall and how does it work

Computers and Technology
1 answer:
valentina_108 [34]3 years ago
3 0

Answer:

Firewalls are software or hardware that work as a filtration system for the data attempting to enter your computer or network. Firewalls scan packets for malicious code or attack vectors that have already been identified as established threats.They are useful to protect and keep your data secured and safe.They can detect hacker id's and won't let them access your data with passwords.Hope this answer helps

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Write a program that accepts any number of homework scores ranging in value from 0 through
Dimas [21]

Answer:

This program is written in Java programming language.

It uses an array to store scores of each test.

And it also validates user input to allow only integers 0 to 10,

Because the program says the average should be calculated by excluding the highest and lowest scores, the average is calculated as follows;

Average = (Sum of all scores - highest - lowest)/(Total number of tests - 2).

The program is as follows (Take note of the comments; they serve as explanation)

import java.util.*;

public class CalcAvg

{

public static void main(String [] args)

{

 Scanner inputt = new Scanner(System.in);

 // Declare number of test as integer

 int numTest;

 numTest = 0;

 boolean  check;

  do

  {

   try

   {

     Scanner input = new Scanner(System.in);

    System.out.print("Enter number of test (1 - 10): ");

    numTest = input.nextInt();

    check = false;

    if(numTest>10 || numTest<0)

     check = true;

   }

   catch(Exception e)

    {

     check = true;

   }

  }

  while(check);

  int [] tests = new int[numTest];

//Accept Input

for(int i =0;i<numTest;i++)

{

System.out.print("Enter Test Score "+(i+1)+": ");

tests[i] = inputt.nextInt();

}

           //Determine highest

           int max = tests[0];

           for (int i = 1; i < numTest; i++)

           {

               if (tests[i] > max)

               {

                   max = tests[i];

               }

           }

           //Determine Lowest

           int least = tests[0];

           for (int i = 1; i < numTest; i++)

           {

               if (tests[i] < least)

               {

                   least = tests[i];

               }

           }

           int sum = 0;

           //Calculate total

           for(int i =0; i< numTest;i++)

           {

               sum += tests[i];

           }

           //Subtract highest and least values

           sum = sum - least - max;

           //Calculate average

           double average = sum / (numTest - 2);

           //Print Average

           System.out.println("Average = "+average);

           //Print Highest

           System.out.println("Highest = "+max);

           //Print Lowest

           System.out.print("Lowest = "+least);

}

}

//End of Program

6 0
3 years ago
Chandra, a student working on a group project, is trying to decide how to have the whole group suggest revisions for an essay. S
fenix001 [56]
I believe the appropriate answer would be comments
7 0
3 years ago
A drowsy cat spots a flowerpot that sails first up and then down past an open window. The pot is in view for a total of 0.50 sec
GaryK [48]

Answer:

2.342m

Explanation:

Given

Time = 0.5 s

Height of Window = 2m

Because the pot was in view for a total of 0.5 seconds, we can assume that it took the cat 0.25 seconds to go from the bottom of the window to the top

Using this equation of motion

S = ut - ½gt²

Where s = 2

u = initial velocity = ?

t = 0.25

g = 9.8

So, we have.

2 = u * 0.25 - ½ * 9.8 * 0.25²

2 = 0.25u - 0.30625

2 + 0.30625 = 0.25u

2.30625 = 0.25u

u = 2.30625/0.25

u = 9.225 m/s ------------ the speed at the bottom of the pot

Using

v² = u² + 2gs to calculate the height above the window

Where v = final velocity = 0

u = 9.225

g = 9.8

S = height above the window

So, we have

0² = 9.225² - 2 * 9.8 * s

0 = 85.100625 - 19.6s

-85.100625 = -19.6s

S = -85.100625/19.6

S = 4.342

If 4.342m is the height above the window and the window is 2m high

Then 4.342 - 2 is the distance above the window

4.342 - 2 = 2.342m

6 0
3 years ago
In which type of attack do you get malicious code in links from seemingly reliable websites?
natali 33 [55]

I think it is C. cross-site scripting

6 0
3 years ago
You are trying to appreciate how important the principle of locality is in justifying the use of a cache memory, so you experime
murzikaleks [220]

Answer:

Explanation:

Attached is the solution

3 0
3 years ago
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