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3 years ago

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Part A: The line of best fit for this data is y = 5.3x + 23 . Use this equation to make a conjecture about the temperature of th

e water in the beaker if heated for 6 minutes. Explain your thinking.

1 answer:

Luda [366]3 years ago

3 0

Can you help me with something

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One batch of walnut muffins uses

Sholpan [36]

Answer:

4 cups

Step-by-step explanation:

8 0

3 years ago

Use angle relationships to find the value of x.

Juli2301 [7.4K]

Answer:

x=12.

Step-by-step explanation:

Let's get this straight out of the way, the 3 angles of a triangle ALWAYS add up to 180. Now that that's said, lets begin. Since the opposing side of an angle is the same as the regular side, we simplify to get: 5x+120=180. 180-120=60. so 5x=60. 60/5=12. so x=12.

7 0

2 years ago

Read 2 more answers

In a dance competition, a participant has to score a total of at least 30 points in the first four rounds combined to move on to

Anvisha [2.4K]

Answer:

5 + 3p ≥ 30

Step-by-step explanation:

"at least" means greater than are equal to. ≥

So we already know he has 5 points, but the other 3 rounds we don't. 5 + 3p

30 is the overall points he has.

5 + 3p ≥ 30

4 0

3 years ago

A submarine is at -125 feet in the ocean. The submarine makes 3 dives of 50 feet each. At what level is the submarine after thre

iren2701 [21]

Each dive goes further down, so it represents -50 ft (not positive which would represnt going up).

y= -125-50x

We know that there are 3 dives so plug that in for x
y= -125-50(3)
y= -125-150
y= -275

Final answer: -275 ft

3 0

3 years ago

Read 2 more answers

Will someone help with this ! I was allowed a retry for it and I don’t know how to do it

pashok25 [27]

Answer:

$\frac{dN}{dt}=k(725-N)\\separating the variables and integrating\\\int \frac{dN}{725-N}=\int kdt+c\\-log (725-N)=kt+c\\log (725-N)=-kt-c\\(725-N)=e^{-kt-c} =e^{-kt} *e^{-c} =Ce^{-kt} \\when t=0,N=400\\725-400=Ce^{0} =C\\C=325\\when t=3,N=650\\725-650=325e^{-3k} \\\frac{75}{325}=(e^{-k})^3\\\\e^{-k} =(\frac{3}{13}) ^{\frac{1}{3} } \\when t=5\\725-N=325(\frac{3}{13}) ^{\frac{5}{3} } =325*\frac{3}{13}*(\frac{3}{13} )^{\frac{2}{3}}\\N=725-75*(\frac{3}{13} )^{\frac{2}{3} }=725-28=697$

Step-by-step explanation:

6 0

3 years ago