Answer:
0.027 cubic ft/min
Explanation:
Volume of water is V=V(t) Depth of water is h=h(t)
The relationship between V and h is
V=π/3.r2.h
Let
h0= the height of the cylinder = 24ft, r0= the radius of the opening = 10ft.
Since water level (h) rise with respect to flow rate we find an expression for r and substitute into V
r/h = r0/h0= 10/24 = 5/12
r = (5/12) h,
Substitute for r in V
so,
V=1/3.π.(h2)square = 1/3.π. 25/144.(h3)
When
h= 16ft
and dV/dt = 20ft3/min
,
dV/dt =1/3*π*25/144*h3*(dh/dt)
20ft3/min= 1/3*π* 25/144*h3*(dh/dt)
20 = 1/3*π*(16)3.(dh/dt)
Make dh/DT subject of formula
dh/dt=(20*3*144)/(25*π*4096) = 8640/321740.8
=
dh/dt= 0.027 ft3/min
Answer:
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Explanation:
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