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ryzh [129]
4 years ago
6

Rename 5,400 as hundreds. Includes a quick picture or a place-value chart in your explanation

Mathematics
1 answer:
Bess [88]4 years ago
5 0
No. no. no! no. no. no. no.
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Which of the following is equivalent to
IRISSAK [1]

Answer:

x^{4}

Step-by-step explanation:

\frac{x^{5}y^{2}  }{xy^{2} }

= x^{4}

7 0
4 years ago
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15% of 20 is _____.
faltersainse [42]
15% = 0.15

0.15 x 20 = 3

15% of 20 is 3.
6 0
4 years ago
What is 3 1/4 =3 /12
IrinaVladis [17]
Please rewrite this question in an understandable form.
5 0
3 years ago
Sprinting 5/6 of a lap and then take a break by jogging 1/3 of a lap how much did i sprint than jog
levacccp [35]

Answer:

2/6

since both of these have a common multiply of 6 (3 x 2 = 6 and 6 already being there for the larger one) you would multiply both the 1 and the 3 by 2 so it's easier to solve, and you get 2/6.

6 0
3 years ago
Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).
NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}

Now, differentiate to obtain

\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}

=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}

To obtain the required form, extract a factor in both the numerator and denominator:

\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)

3 0
4 years ago
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