All categories

4 years ago

Rename 5,400 as hundreds. Includes a quick picture or a place-value chart in your explanation

Mathematics

1 answer:

Bess [88]4 years ago

5 0

No. no. no! no. no. no. no.

You might be interested in

Which of the following is equivalent to

IRISSAK [1]

Answer:

$x^{4}$

Step-by-step explanation:

$\frac{x^{5}y^{2} }{xy^{2} }$

= $x^{4}$

7 0

4 years ago

Read 2 more answers

15% of 20 is _____.

faltersainse [42]

15% = 0.15

0.15 x 20 = 3

15% of 20 is 3.

6 0

4 years ago

What is 3 1/4 =3 /12

IrinaVladis [17]

Please rewrite this question in an understandable form.

5 0

3 years ago

Sprinting 5/6 of a lap and then take a break by jogging 1/3 of a lap how much did i sprint than jog

levacccp [35]

Answer:

2/6

since both of these have a common multiply of 6 (3 x 2 = 6 and 6 already being there for the larger one) you would multiply both the 1 and the 3 by 2 so it's easier to solve, and you get 2/6.

6 0

3 years ago

Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).

NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

$1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}$

Now, differentiate to obtain

$\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}$

$=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}$

To obtain the required form, extract a factor in both the numerator and denominator:

$\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)$

3 0

4 years ago