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Travka [436]
3 years ago
14

The second side of a triangular deck is 3 feet longer than the shortest side and a third side that is 3 feet shorter than twice

the length of the shortest side. if the perimeter of the deck is 80 feet, what are the lengths of the three sides?
Mathematics
1 answer:
matrenka [14]3 years ago
7 0

Answer:

Shortest Side = 20 feet

Second Side = 23 feets

Third Side = 37 feets

Step-by-step explanation:

Let the shortest side of the desk be x. Hence,

Second side = (x + 3) feets

Third side = (2x - 3) feets

Perimeter = 80ft

x + (x + 3) + (2x - 3) = 80

                          4x = 80

                             x = 20

Hence, Second side = (20 + 3) feets

                                  = 23 feets

Third side = (40 - 3) feets

                 = 37 feets

Hence<u>,</u><u> shortest side is 20 feets, Second side is 23 feets, Third side is 37 feets.</u>

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Answer:

It will cost $4.50 for 9 kiwis

Step-by-step explanation:

Lets find the cost per kiwi

$3 / 6 kiwis

.50 per kiwi

Now we have 9 kiwis

$.50 (9)

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It will cost $4.50 for 9 kiwis

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3 years ago
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8(x) = x^3 - 3<br> What is the value of x when g(x) = 24? Enter the answer in the box.
IRINA_888 [86]

Answer:

x=3

Step-by-step explanation:

x³ - 3 =24

x³ = 27

x = 3

6 0
3 years ago
Se quiere construir un muro de 4 m de alto, 12 m de largo y 10 cm de espesor. ¿Cuántos ladrillos de 8 cm de alto, 20 cm de largo
Llana [10]

Answer:

3000

Step-by-step explanation:

Let's start by finding the volume of the wall. The volumen of the wall can be considered as the volume of a rectangular prism. The volume of a rectangular prism is given by:

V_w=w*l*h\\\\Where:\\\\w=Width=10cm=0.1m\\l=Length=12m\\h=Height=4m

So the volume of the wall is:

V_w=0.1*12*4=4.8m^3

Now, we can find the volume of the brick using the same method since a brick can be considered as a rectangular prism as well:

V_b=w*l*h\\\\For\hspace{3}the\hspace{3}brick\\\\w=10cm=0.1m\\l=20cm=0.2m\\h=8cm=0.08m

Hence:

V_b=(0.1)*(0.2)*(0.08)=0.0016m^3

In order to know how many bricks are required to build the wall, we just need to fill the wall volume with the number of bricks of this volume. So:

V_w=nV_b\\\\Where\\\\n=Number\hspace{3}of\hspace{3}bricks

Solving for n:

n=\frac{V_w}{V_b} =\frac{4.8}{0.0016} =3000

Therefore, we need 3000 bricks to build that wall.

Translation:

Comencemos por encontrar el volumen del muro. El volumen del muro puede considerarse como el volumen de un prisma rectangular. El volumen de un prisma rectangular viene dado por:

V_w=w*l*h\\\\Donde:\\\\w=Espesor=10cm=0.1m\\l=Largo=12m\\h=Alto=4m

Entonces el volumen del muro es:

V_w=0.1*12*4=4.8m^3

Ahora, podemos encontrar el volumen del ladrillo utilizando el mismo método, ya que un ladrillo también puede considerarse como un prisma rectangular:

V_b=w*l*h\\\\Para\hspace{3}el\hspace{3}ladrillo\\\\w=10cm=0.1m\\l=20cm=0.2m\\h=8cm=0.08m

Por lo tanto:

V_b=(0.1)*(0.2)*(0.08)=0.0016m^3

Para saber cuántos ladrillos se requieren para construir el muro, solo necesitamos llenar el volumen del muro con la cantidad de ladrillos de este volumen. Entonces:

V_w=nV_b\\\\Donde\\\\n=Numero\hspace{3}de\hspace{3}ladrillos

Resolviendo para n:

n=\frac{V_w}{V_b} =\frac{4.8}{0.0016} =3000

Por lo tanto, necesitamos 3000 ladrillos para construir ese muro.

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Answer:

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Please consider the attached graph.

We have been given that measure of angle 3 is 29°. We are asked to find the measure of angle 4.

Upon looking at our diagram, we can see that angle 3 and angle 4 are linear angles.

We know that linear angles add up-to 180 degrees, so the sum of measure of angle 3 and angle 4 will be 180 degrees.

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m\angle 4=151^{\circ}

Therefore, the measure of angle 4 is 151 degrees.

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