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2 years ago

7

A rhombus is constructed on side AD¯¯¯¯¯ of figure ABCD such that FA¯¯¯¯¯ lies on AB←→ as shown. If AD : AB = 2 : 5, what is the

x-coordinate of point F?
A.) 1.7
b.) 2.9
c.) 3.8
d.) 4.4

2 answers:

Paladinen [302]2 years ago

8 0

Answer:

The answer is D)4.4

Step-by-step explanation:

Oxana [17]2 years ago

3 0

The x coordinate of f is 4.4 i think im not sure

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Answer:

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Step-by-step explanation:

We have been given that the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation $y=-16x^2+224x+121$ . We are asked to find the time, when the rocket will hit the ground.

We know that the rocket will hit the ground, when height will be 0. So to find the time when rocket will hit the ground, we will substitute $y=0$ in our given equation as:

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Let us solve for x using quadratic formula.

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

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$x=\frac{-224\pm\sqrt{50176+7744}}{-32}$

$x=\frac{-224\pm\sqrt{57920}}{-32}$

$x=\frac{-224\pm240.66574}{-32}$

$x=\frac{-224+240.66574}{-32}, x=\frac{-224-240.66574}{-32}$

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Upon rounding to nearest 100th of second, we will get:

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