Question

If the diffrence in the side lenghts of two squares is 10,and the sum of the side lenghts is 18, what are the side lengths

Answer 1

Answer:

The side of first square =14 units  

side of second square =4 units

Step-by-step explanation:

We have given two squares,

A square have all its four sides equal and at right angles.

Let the side of first square be 'a'

and the side of second square be 'b'

Given:

                 $a-b=10$     equation:1

                $a+b=18$   equation:2

Solving equation:1  

                      a=10+b      equation:3

Putting 'a' in equation:2

                           $(10+b)+b=18\\\\2b=18-10\\\\2b=8\\\\b=4$

Putting 'b' in  equation:3

          $a=10+4\\\\a=14$

So, the side of first square is 14 units and

side of second square is 4 units