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VARVARA [1.3K]
3 years ago
6

If the diffrence in the side lenghts of two squares is 10,and the sum of the side lenghts is 18, what are the side lengths

Mathematics
1 answer:
konstantin123 [22]3 years ago
5 0

Answer:

The side of first square =14 units  

side of second square =4 units

Step-by-step explanation:

We have given two squares,

A square have all its four sides equal and at right angles.

Let the side of first square be 'a'

and the side of second square be 'b'

Given:

                 a-b=10     equation:1

                a+b=18   equation:2

Solving equation:1  

                      a=10+b      equation:3

Putting 'a' in equation:2

                           (10+b)+b=18\\\\2b=18-10\\\\2b=8\\\\b=4

Putting 'b' in  equation:3

          a=10+4\\\\a=14

So, the side of first square is 14 units and

side of second square is 4 units

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mafiozo [28]

Question 7

<h3>Answer: A) 15</h3>

---------------------

Work Shown:

angle B = angle D = 56

angle C = angle F = 64

The missing angle A adds with B and C to get 180

A+B+C = 180

A = 180-B-C

A = 180-56-64

A = 60

Since angles B and D are congruent, and C and F are congruent, this must mean angle A = angle E. I'm using the angle angle (AA) similarity rule.

angle E = angle A

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================================================

Question 8

<h3>Answer: B) 17</h3>

------------------------------

Work Shown:

Triangle ABC is congruent to triangle EDF. The order is important. We have A first, then B, then C for ABC. Also, we have E first, then D, then F for EDF.

Therefore, we have these three pairings

  • angle A = angle E
  • angle B = angle D
  • angle C = angle F

We'll first need angle C

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C = 180-A-B

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4x-4 = 30

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4x = 34

x = 34/4

x = 8.5

which doubles to

2x = 2*8.5

2x = 17

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