If the diffrence in the side lenghts of two squares is 10,and the sum of the side lenghts is 18, what are the side lengths
1 answer:
Answer:
The side of first square =14 units
side of second square =4 units
Step-by-step explanation:
We have given two squares,
A square have all its four sides equal and at right angles.
Let the side of first square be 'a'
and the side of second square be 'b'
Given:
equation:1
equation:2
Solving equation:1
a=10+b equation:3
Putting 'a' in equation:2
Putting 'b' in equation:3
So, the side of first square is 14 units and
side of second square is 4 units
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Explanation:
The question states:
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Explanation:
The question states:
1) sin(Θ) = 1/4
2) 0 < Θ < π / 2
3) find cos(Θ)
This is how you solve it.
1) Use the fundamental identity (in this part I use α instead of Θ, just for facility of wirting the symbols, but they mean the same for the case).
2) From which you can find:
3) Replace sin(α) with 1/4
=>
=>
4) Given that the angle is in the first quadrant, you know that cosine is positive and the final answer is:
cos(Θ) =
And that is the answer.