All categories

3 years ago

If the distance and time is known how would you use the distance formula to determine the rate that a car travels

Mathematics

1 answer:

topjm [15]3 years ago

4 0

Answer:

Distance traveled / time taken

Step-by-step explanation:

Given :

The distance traveled by a car and the time taken to cover the distance

Take :

Distance = d

Time taken to cover distance = t

The rate the car travels is related by the equation :

Speed or rate = Distance traveled / time taken

You might be interested in

The Lars family has a moisture farm on the planet Tatooine. They owned 5 acres of land. They sold 2/7 of their land to the Tuske

jeka57 [31]

Answer:

25/7 acres or 3 4/7 acres

Step-by-step explanation:

The sold 2/7 of the land.

1 - 2/7 = 7/7 - 2/7 = 5/7

They have 5/7 of the land left.

5/7 of 5 acres = 5/7 × 5 acres = 25/7 acres = 3 4/7 acres

7 0

2 years ago

How do I answer this question pls help me

n200080 [17]

Answer:

14.7 quarts

Step-by-step explanation:

Use the given equivalence figures to write a proportion. Solve the proportion for the unknown value.

quarts/liters = x/14 = 1/0.95 . . . . . the conversion is given as 1 qt = 0.95 L

Multiply by 14 to find x.

x = 14(1/0.95) ≈ 14.7

There are about 14.7 quarts in 14 liters.

_____

Additional comment

You are given a value in liters (14 liters) and asked for the equivalent in quarts. That means you want to change the units from liters to quarts. To do that, you can multiply the given value (14 liters) by a conversion factor that has quarts in the numerator and liters in the denominator. That is what the fraction 1/0.95 is in the above. You will note that units of liters cancel in this equation.

$(14\text{ liters})\times\dfrac{1\text{ quart}}{0.95\text{ liter}}=\dfrac{14}{0.95}\text{ quarts}\approx14.7\text{ quarts}$

This rule, "use a conversion factor that divides by the units you don't want and multiplies by the units you do want" applies to any units conversion problem. The conversion factor you use should always have equal quantities in the numerator and denominator. (Here, the equal quantities are 1 quart and 0.95 liters.)

You will notice that we treat units just like any variable. They can be multiplied, divided, cancelled, raised to a power. Only terms with like units can be added or subtracted.

4 0

2 years ago

8. The two triangles are congruent as suggested by their appearance. Find the value of all the variables. The

adelina 88 [10]

Answer: d is 53 degrees, c is 5, g is 13, e is 90 degrees, f is 37 degrees, b is 12 .

Step-by-step explanation:

Since they're congruent you just compare the two and replace them. You have the answers on both sides, they're just split up. So look at one side, then the other, and see what you can find. Repeat.

8 0

3 years ago

Read 2 more answers

A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300. The

zubka84 [21]

Answer:

the variance of the refund payment to the couple = 9463.394

Step-by-step explanation:

Given that :

A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300.

It is possible that the couple won't be able to refund up 100 per day or more than 100 per day.

SO; let assume that the refund payment happens to be 0, 100,200, 300

Let X be the total refund payment on the seven day cruise.

We can say X = 0, if there is no rain on all 7 days.

$P(X = 0) = _nC_x * P^x * (1 - P)n-x$

$P(X = 0) = _7C_o * 0.2^0 * (1-0.2)^{7-0$

$P(X = 0) =1 * 1* (1-0.2)^{7$

$P(X = 0) =(0.8)^{7$

$P(X = 0) =0.2097152$

If it rains on any one day; then X = 100

$P(X = 100) = _nC_x * P^x * (1 - P)n-x$

$P(X = 100) = _7C_1 * 0.2^1 * (1-0.2)^{7-1$

$P(X = 0) =7 * 0.2* (1-0.2)^{6$

$P(X = 100) =7* 0.2* (0.8)^{6$

$P(X = 100) =0.3670016$

if it rains on any two day ; then X = 200

$P(X = 200) = _nC_x * P^x * (1 - P)n-x$

$P(X = 200) = _7C_2 * 0.2^2 * (1-0.2)^{7-2$

$P(X = 200) = 21 * 0.2^2 * (0.8)^{5$

$P(X = 200) = 0.2752512$

if it rains on any three day or more than that ; then X = 300

$P(X \ge 300) = 1 - P(X < 300) \\ \\ P(X \ge 300) = 1 - [P(X = 0) + P(X = 100) + P(X = 200)] \\ \\ P(X \ge 300) = 1 - [0.2097152 + 0.3670016 + 0.2752512] \\ \\ P(X \ge 300) = 0.148032$

Now; we have our probability distribution function as:

P(X = 0) = 0.2097152

P(X = 100) = 0.3670016

P(X = 200) = 0.2752512

P(X = 300) = 0.148032

In order to determine the variance of the refund payment to the couple; we use the formula:

variance of the refund payment to the couple $[Var X] =E [X^2] - (E [X])^2$

where;

$E[X^2] = \sum x^2 \times p \\ \\ E[X^2] = 0^2 * 0.2097152 + 100^2 * 0.3670016 + 200^2 * 0.2752512 + 300^2 * 0.148032 \\ \\ E[X^2] = 0 + 3670.016 + 11010.048+ 13322.88 \\ \\ E[X^2] =28002.944$

$(E [X]) = \sum x * p\\ \\ (E [X]) = 0 * 0.2097152 + 100 * 0.3670016 + 200 * 0.2752512 + 300 * 0.148032 \\ \\ (E [X]) = 0 + 36.70016 + 55.05024 + 44.4096\\ \\ (E [X]) = 136.16 \\ \\ (E [X])^2 = 136.16^2 \\ \\ (E [X])^2 = 18539.55$