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3 years ago

Pleaseeeeeeeeeeee helpppppppp

Mathematics

2 answers:

KiRa [710]3 years ago

8 0

I agree with Redhood d. because if you do 50 x 6 youw would get 300.

Nesterboy [21]3 years ago

3 0

D. 300 it is. is there more?

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What is the solution of the equation 9^2x=6? Round your answer to the nearest ten-thousandth.

sammy [17]

Answer:

0.4077

Step-by-step explanation:

It's important to use parenthesis to avoid confusion.

9^(2x) = 6

Use exponent properties:

(9^2)^x = 6

81^x = 6

Take log of both sides

ln(81^x) = ln(6)

Use log properties:

x ln(81) = ln(6)

Solve for x:

x = ln(6) / ln(81)

x ≈ 0.4077

4 0

2 years ago

What is the answer? 5(6x-2) = -250

faust18 [17]

Answer:

x = -8

Step-by-step explanation:

5(6x-2) = -250

30x - 10 = -250

30x/(30) = -240/(30)

x = -8

4 0

3 years ago

Read 2 more answers

Work out the lengths of sides a and b.

nlexa [21]

Answer:

No solution is possible since you failed to provide the necessary information

Step-by-step explanation:

3 0

2 years ago

Suppose a baker claims that the average bread height is more than 15cm. Several of this customers do not believe him. To persuad

laila [671]

Answer:

$17-2.262\frac{1.9}{\sqrt{10}}=15.641$

$17+2.262\frac{1.9}{\sqrt{10}}=18.359$

So on this case the 95% confidence interval would be given by (15.641;18.359)

And since the lower limit for the confidence interval is higher than 15 we can conclude that at 5% of significance the true mean is higher than 15 cm

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=17$ represent the sample mean

$\mu$ population mean (variable of interest)

s=1.9 represent the sample standard deviation

n=10 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=10-1=9$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,9)".And we see that $t_{\alpha/2}=2.262$