What are a) the ratio of the perimeters and b) the ratio of the ratio of the areas of the larger figure to the smaller figure

2 answers:

8 0

Assuming that the figures given are square such that the scale factor between them is equal to 28/8 which can be further simplified into 7/2. The ratio of the perimeter is also equal to this value, 7/2. However, the ratio of the areas is equal to the square of this value giving us an answer of 49/4.

Naya [18.7K]2 years ago

6 0

Answer:

the answer is b

Step-by-step explanation:

7/2 and 49/4

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Elliot is buying groceries. He buys a bag of apples for 5.54, a loaf of bread for 2.49, and a jar of peanut butter for 3.73. Ell

zloy xaker [14]

Answer:

Step-by-step explanation:

First, you want to add up the subtotal together, so its 5.54+2.49+3.73, and adding those together you get 11.76 as your subtotal. To figure out change, you simply subtract your subtotal to the amount he paid in. For that it is 20-11.76, and that is 8.24

Elliot gets $8.24 in change.

Hope this helps.

7 0

3 years ago

If 3x^2 + y^2 = 7 then evaluate d^2y/dx^2 when x = 1 and y = 2. Round your answer to 2 decimal places. Use the hyphen symbol, -,

S_A_V [24]

Taking $y=y(x)$ and differentiating both sides with respect to $x$ yields

$\dfrac{\mathrm d}{\mathrm dx}\bigg[3x^2+y^2\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[7\bigg]\implies 6x+2y\dfrac{\mathrm dy}{\mathrm dx}=0$

Solving for the first derivative, we have

$\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x}y$

Differentiating again gives

$\dfrac{\mathrm d}{\mathrm dx}\bigg[6x+2y\dfrac{\mathrm dy}{\mathrm dx}\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[0\bigg]\implies 6+2\left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2+2y\dfrac{\mathrm d^2y}{\mathrm dx^2}=0$

Solving for the second derivative, we have

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=-\dfrac{3+\left(\frac{\mathrm dy}{\mathrm dx}\right)^2}y=-\dfrac{3+\frac{9x^2}{y^2}}y=-\dfrac{3y^2+9x^2}{y^3}$

Now, when $x=1$ and $y=2$ , we have

$\dfrac{\mathrm d^2y}{\mathrm dx^2}\bigg|_{x=1,y=2}=-\dfrac{3\cdot2^2+9\cdot1^2}{2^3}=\dfrac{21}8\approx2.63$

3 0

3 years ago

What happens to the center of a figure when it is dilated about the origin?

alina1380 [7]

There are 2 answers for this in my opinion
1. nothing happens because its still in the origin and that won't change
2. depending on which way you turn it the points will change based on that

so if you know how to use a graph you should be good

7 0

3 years ago

Expand to write an equivalent expression -1/2 (-6x+8y) <br><br>(Pleasee help i need an answer rqqqq)

Alik [6]

Answer:

$- \frac{1}{2} ( - 6x + 8y) \\ = \frac{1}{2} (6x - 8y) \\ = 3x - 4y$