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Answer:
BD = 17
Step-by-step explanation:
The Pythagorean theorem can be used twice:
BC^2 + AC^2 = AB^2
BC = √(AB^2 -AC^2) = √(25^2 -24^2) = √49 = 7
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Likewise, ...
DC = √(AD^2 -AC^2) = √(26^2 -24^2) = √100 = 10
Then ...
BD = BC +DC = 7 + 10
BD = 17
Answer:
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Assume θ with a value and substitute with it.
Let θ = 45°
So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2
R.H.S = cot θ = cot 45 = 1
So, L.H.S ≠ R.H.S
So, sin θ cos θ = cot θ is not a trigonometric identity.
First number is (x).
Second number is (2x+7).
Third number is (x-12).
Their sum is (x+2x+7+x-12).
x+2x+7+x-12 =131
You can simplify this equation
4x-5=131,
4x=136
x=136/4=34 (first number),
(2x+7)=34*2+7=75 (second number)
34-x=34-12 =22(third number)
Check: 34+75+22=131
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Answer:
c
Step-by-step explanation:
