The sum of three numbers is 131. The second of three numbers is seven more than twice the first. The third number is 12 less tha

Question

Xelga [282]

3 years ago

5

The sum of three numbers is 131. The second of three numbers is seven more than twice the first. The third number is 12 less tha

n the first. What equation can be used to solve the problem?

Mathematics

1 answer:

Norma-Jean [14] · Answer 1 · 2022-07-20T00:56:07+03:00

Norma-Jean [14]3 years ago

6 0

First number is (x).
Second number is (2x+7).
Third number is (x-12).
Their sum is (x+2x+7+x-12).
x+2x+7+x-12 =131

You can simplify this equation
4x-5=131,

4x=136
x=136/4=34 (first number),
(2x+7)=34*2+7=75 (second number)
34-x=34-12 =22(third number)

Check: 34+75+22=131