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Xelga [282]
3 years ago
5

The sum of three numbers is 131. The second of three numbers is seven more than twice the first. The third number is 12 less tha

n the first. What equation can be used to solve the problem?
Mathematics
1 answer:
Norma-Jean [14]3 years ago
6 0
First number is (x).
Second number is (2x+7).
Third number is (x-12).
Their sum is  (x+2x+7+x-12).
x+2x+7+x-12 =131

You can simplify this equation
4x-5=131,

4x=136
x=136/4=34 (first number), 
(2x+7)=34*2+7=75 (second number)
34-x=34-12 =22(third number)

Check: 34+75+22=131
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