Answer: There are 720 ways to do so.
Step-by-step explanation:
Since we have given that
Number of spaces in a flagpole = 10
Number of types of flag = 3
Number of spaces for red flag = 1
Number of spaces for green flag = 1
Number of spaces for blue flag = 1
We will use "Fundamental theorem of counting":
So, Number of ways that the 10 spaces of the flagpole can be covered with flags such that no spaces is empty is given by
Hence, there are 720 ways to do so.
Answer:
How do you find the equilibrium price with a supply and demand function?
To determine the equilibrium price, do the following.
Set quantity demanded equal to quantity supplied:
Add 50P to both sides of the equation. You get.
Add 100 to both sides of the equation. You get.
Divide both sides of the equation by 200. You get P equals $2.00 per box. This is the equilibrium price.
If we were to imagine a single point (1,1) which is in quadrant 1, and we rotate it 90o then we get a negative x. Another 90o then both x and y is negative. another 90 (270) and we get a negative y.
thus:
(e)(f)(g)(h) = (-1,-1)(-1,-2)(-2,-1)(-2,-2)
Hey there :)
Now lets name each house
A B C D E F
500ft <-> 500ft <-> 500ft <-> 500ft <-> 500ft <-> 2000ft
Let's say the bus stops at A
= 0 ( from A ) + 500 ( from B ) + 500 + 500 ( from C ) + 500 + 500 + 500 ( from D ) + 500 + 500 + 500 + 500 ( from E ) + 500 + 500 + 500 + 500 + 2000 ( from F )
= 0 + 500 + 1000 + 1500 + 2000 + 4000
= 9000 ft
at B
= 500 ( from A ) + 0 ( from B ) + 500 ( from C ) + 500 + 500 ( from D ) + 500 + 500 + 500 ( from E ) + 500 + 500 + 500 + 2000 ( from F )
= 500 + 0 + 500 + 1000 + 1500 + 3500
= 7000 ft
at C
= 500 ( from A ) + 500 + 500 ( from B ) + 0 ( from C ) + 500 ( from D ) + 500 + 500 ( from E ) + 500 + 500 + 2000 ( from F )
= 500 + 1000 + 0 + 500 + 1000 + 3000
= 6000 ft
Do the same for D , E and F
at D
= 6000 ft
at E
= 7000 ft
at F
= 15000 ft
You will find that the bus should stop at either C or D to make the sum of distances from every house to the stop as small as possible.
Find the TWO places where the graph crosses the x axis;. solve; find the roots; find the zeros; it is entirely possible that the equation has no real roots meaning it has imaginary or complex roots