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sveta [45]
3 years ago
6

What are the similarities and differences between types of quadrilaterals? Plz help me in math exam ans his qnn i will mark as b

rainliesttt ⚠
Mathematics
1 answer:
insens350 [35]3 years ago
5 0

Answer:

Look below

Step-by-step explanation:

There are many different kinds of quadrilaterals, but all have several things in common: all of them have four sides, are coplanar, have two diagonals, and the sum of their four interior angles equals 360 degrees.

Some differences include the shape and the number of parallel sides each quadrilateral has

Hope this helps :)

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What is the domain of the relation y = arccscx?
Stella [2.4K]

Answer:

y=arc\csc x

Step-by-step explanation:

The given function is y=arc\csc x.

The domain refers to all values of x for which this function is defined.

Recall that: the domain of y=arc \sin (x) is -1\le x\le1

And we know y=arc\csc x is the reciprocal of y=arc \sin (x).

Therefore the complement of the domain of y=arc \sin (x) which is (-\infty,-1]\cup [1,+\infty) is the domain of y=arc\csc x

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3 years ago
The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st
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Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

v=\frac{d}{t}.

Applying this to our problem we have that

v=\frac{200m}{6.509s}= 30.726m/s.

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that v=\frac{d}{t}. This formula implies that

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First, observer that 19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s.

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.

Then, applying 1) we have that

t=\frac{200m}{36.003m/s}=5.5549s.

So, Sam Whittingham’s time through the 200 m was 5.5549s.

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