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dem82 [27]
3 years ago
6

For a right circular cylinder, if the radius is tripled and the hight is shrunk down to half its size then what is the surface a

reas if the origin radius is 7 inches and the original height is 17 inches
Mathematics
1 answer:
IrinaK [193]3 years ago
6 0

Answer:

Surface area of right circular cylinder = 1,122 inches²

Step-by-step explanation:

Given:

Origin radius = 7 inches

Original height = 17 inches

New radius = 7 × 3 inches = 21 inches

New height = 1/2(17) = 8.5 inches

Find:

Surface area of right circular cylinder = ?

Computation:

⇒ Surface area of right circular cylinder = 2\pirh

⇒ Surface area of right circular cylinder = 2 × (22/7) × (21) × (8.5)

⇒ Surface area of right circular cylinder = 1,122 inches²

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At the beginning of year 1, Bode invests $250 at an annual simple interest rate of 3%. He makes no deposits to or withdrawals fr
Dennis_Churaev [7]
The initial investment = $250
<span>annual simple interest rate of 3% = 0.03
</span>
Let the number of years = n
the annual increase = 0.03 * 250
At the beginning of year 1 ⇒ n = 1 ⇒⇒⇒ A(1) = 250 + 0 * 250 * 0.03 = 250

At the beginning of year 2 ⇒ n = 2 ⇒⇒⇒ A(2) = 250 + 1 * 250 * 0.03
At the beginning of year 3 ⇒ n = 3 ⇒⇒⇒ A(2) = 250 + 2 * 250 * 0.03
and so on .......
∴ <span>The formula that can be used to find the account’s balance at the beginning of year n is:
</span>
A(n) = 250 + (n-1)(0.03 • 250)
<span>At the beginning of year 14 ⇒ n = 14 ⇒ substitute with n at A(n)</span>
∴ A(14) = 250 + (14-1)(0.03*250) = 347.5

So, the correct option is <span>D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50 </span>
4 0
4 years ago
Read 2 more answers
What is the solution of the equation (x – 5)^2 + 3(x – 5) + 9 = 0? Use u substitution and the quadratic formula to solve.
xz_007 [3.2K]

Answer:

x = \dfrac{7 \pm 3i\sqrt{3}}{2}

Step-by-step explanation:

(x – 5)^2 + 3(x – 5) + 9 = 0

This is a quadratic equation in x - 5.

Let u = x - 5, then the quadratic equation becomes:

u^2 + 3u + 9 = 0

We can use the quadratic formula to solve for u.

u = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

u = \dfrac{-3 \pm \sqrt{3^2 - 4(1)(9)}}{2(1)}

u = \dfrac{-3 \pm \sqrt{9 - 36}}{2}

u = \dfrac{-3 \pm \sqrt{-27}}{2}

u = \dfrac{-3 \pm 3i\sqrt{3}}{2}

Since u = x - 5, now we substitute x - 5 for u and solve for x.

x - 5 = \dfrac{-3 \pm 3i\sqrt{3}}{2}

x = \dfrac{-3 \pm 3i\sqrt{3}}{2} + 5

x = \dfrac{-3 \pm 3i\sqrt{3}}{2} + \dfrac{10}{2}

x = \dfrac{7 \pm 3i\sqrt{3}}{2}

7 0
3 years ago
A security fence encloses a rectangular area on one side of a park in a city. three sides of fencing are? used, since the fourth
alexandr1967 [171]
Let x = length of the park
Let y = width of the park

Because the area is 392392 ft², therefore
xy = 392392          (1)
Because three sides of fencing measure 5656 ft, therefore
2x + y = 5656        (2)
That is
y = 5656 - 2x          (3)
Substitute (3) into (1).
x(5656 - 2x) = 392392
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x² - 2828x + 196196 = 0

Solve with the quadratic formula.
x = (1/2)*[2828 +/- √(2828² - 4*196196)]
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Answer:
The possible dimensions are 2756.8 ft and 71.2 ft (nearest tenth)
3 0
3 years ago
Estimate 0.028634791 to the nearest hundredth
Zanzabum

Answer:

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Step-by-step explanation:

the two is in the hundredth place

look next door 5 or more round next door 4 or less let is rest

8 bigger than 5 so 2 goes to 3

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