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nika2105 [10]
3 years ago
10

What is the value of x if a rectangle has a perimeter of 50, a length of x + 5, and width of 11?

Mathematics
1 answer:
Iteru [2.4K]3 years ago
6 0

The perimeter of a polygon is the sum of the lengths of all its sides. A rectangle has 4 sides, and opposite sides are congruent, so 2 sides have length x + 5, and 2 sides have length 11. Add all the lengths and set the sum equal to 50. Then solve the equation for x.

x + 5 + x + 5 + 11 + 11 = 50

2x + 32 = 50

2x = 18

x = 9

Answer: x = 9

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3 years ago
PLS HELP WITH THIS MATH
laiz [17]
I think it’s 28.35

54/100 x 5 = 2.7
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6 0
2 years ago
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Help....................
Romashka-Z-Leto [24]

Answer:

The interquartile range is <em>50.</em>

Step-by-step explanation:

To find our answer we have to first <em>quartile 1</em> and <em>quartile 3</em> are equal too. When we look at the plot <em>quartile 1  </em>is equal to <em>20,</em> <em>quartile 3 </em>is equal to <em>70</em> because it is in between <em>60</em> and <em>80</em>.  Now to find the interquartile range we will <em>subtract 70</em> from <em>20</em> and we get <em>50</em>.  Therefore, <u><em>50</em></u><em> is our answer.</em>

7 0
2 years ago
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