C = 2 pi r
C = 2 x 3.14 x 5
C = 31.4 yd
A = pi r^2
A = 3.14 x 5^2
A = 3.14 x 25
A = 78.5 yd^2
Answer:
5
Step-by-step explanation:
a = 3; b = -2
a - b = 3 - (-2) = 3 + 2 = 5
Answer:
what do you need help with, your imagine isnt loading
Step-by-step explanation:
Answer:
The first mechanic $90/hour and the second charged $70/hour
Step-by-step explanation:
Lets start off by letting x be the first mechanics rate and y being the second mechanics rate. We know that the first mechanic worked 5 hours and that the second mechanic worked 10 hours and together they charged 1150. An equation to express this would be:
5x+10y = 1150
We also know that together they charged 160/per hour. An equation to express this would be:
x+y = 160
Now we can solve the second equation for x or the first mechanics rate.
x+y = 160
x = 160 - y
Now that we have an expression for x we can plug that back into the first equation and solve for y or how much the second mechanic charged.
5x+10y=1150 plug in x =160-y
5(160-y)+10y=1150 Distribute
800 -5y+10y = 1150 Combine like terms
800 +5y = 1150 Subtract 800 from both sides
5y = 350 divide by 5
y = 70
So we know that the second mechanic charged $70/hour. We also know that(from our work before) that the first mechanic charges $160 - the rate the second mechanic charged. We know that's $70/hour so we can plug in and solve for the first rate.
x = 160-y
x = 160-70
x = 90
So we know that the first mechanic charged $90/hour and the second mechanic charged $70/hour.
