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3 years ago

Write a unit rate for the situation. 880 calories in 8 servings

Mathematics

1 answer:

enyata [817]3 years ago

5 0

Answer:

It would be 110 calories per serving

Step-by-step explanation:

So a unit rate is measuring how much of something is there if one unit of another thing is present. In this case, there are 8 servings and 880 calories. Now, simply divide both sides by 8 in order to get the unit rate for each serving:

880/8 ---> 110 calories per serving

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BRUH what is 14x(8-10)=6

bogdanovich [222]

Answer:

0.18

Step-by-step explanation:

14x(8-10)=6

Distribute 14x

112x-80x=6

32x=6

6/32=0.18

x=0.18

Hope this helps

........and is right :p

6 0

3 years ago

Is 7 asolution for the equation 2x + 12=3x +(-2x + 5)

olchik [2.2K]

Answer:

Step-by-step explanation:

2X + 12=13x - 2x + 5

2X + 12= 11x+5

2x-11x = 5-12

-9x = -7

X = 7/9

so the answer is NO

4 0

3 years ago

A statistician is testing the null hypothesis that exactly half of all engineers will still be in the profession 10 years after

lana [24]

Answer:

95% confidence interval estimate for the proportion of engineers remaining in the profession is [0.486 , 0.624].

(a) Lower Limit = 0.486

(b) Upper Limit = 0.624

Step-by-step explanation:

We are given that a statistician is testing the null hypothesis that exactly half of all engineers will still be in the profession 10 years after receiving their bachelor's.

She took a random sample of 200 graduates from the class of 1979 and determined their occupations in 1989. She found that 111 persons were still employed primarily as engineers.

Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of persons who were still employed primarily as engineers = $\frac{111}{200}$ = 0.555

n = sample of graduates = 200

p = population proportion of engineers

<em>Here for constructing 95% confidence interval we have used One-sample z proportion test statistics.</em>

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level of

significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

<u>95% confidence interval for p</u> = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.555-1.96 \times {\sqrt{\frac{0.555(1-0.555)}{200} } }$ , $0.555+1.96 \times {\sqrt{\frac{0.555(1-0.555)}{200} } }$ ]

= [0.486 , 0.624]

Therefore, 95% confidence interval for the estimate for the proportion of engineers remaining in the profession is [0.486 , 0.624].

7 0

3 years ago

If Jeff hikes 1/2 a distance in 1/4 an hour how fast can he walk in 1/2 an hour?<br>

lakkis [162]

Answer:

2/4? i think....

idrk sry :(

Step-by-step explanation:

3 0

3 years ago

Select the correct scientific notation form of this numeral.

ioda

The scientific notation for the number 1063 is 1.063×10³ after using the concept of fraction option (B) 1.063×10³ is correct.

<h3>What is the number?</h3>

A number is a mathematical entity that can be used to count, measure, or name things. For example, 1, 2, 56, etc. are the numbers.

It is given that:

The number is 1063

As we know the scientific notation can be written as:

$\rm = A\times10^a$

1063 can be written as:

= 1063

= (1063/1000)1000

1.063×10³

Thus, the scientific notation for the number 1063 is 1.063×10³ after using the concept of fraction option (B) 1.063×10³ is correct.

Learn more about the number here:

brainly.com/question/17429689

#SPJ1

8 0

2 years ago