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vladimir1956 [14]
4 years ago
13

What is the approximate distance around the half circle with radius 35 inches?

Mathematics
1 answer:
Alexeev081 [22]4 years ago
7 0
Since,
r = 35 inches & Circumference = 2πr
Therefore,
C = 2 * 22/7 *35
C = 2 * 110
C = 220 inches
Therefore, half the distance covered = 110 inches
Since, 109.9 is closest to 110
Therefore,
The correct option is 'C'
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Answer: i'm sorry it does not make any since

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If you need 8 oz of chocolate chips to make 1.6 lb of cookie dough how many ounces of chocolate chips will you need to make 7 lb
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Answer:

3.5 Oz of chocolate

Step-by-step explanation:

1.6 lb of cookie dough is made from chocolate of 8 Oz

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7lb of cookie dough will be made from 7 * 0.5= 3.5 Oz of chocolate/

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Which economic indicator measures inflation<br>A) GDPB) CPI <br>C) unemployment rate
Anastaziya [24]
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8 0
4 years ago
What is the inverse of f (x)=10-×^2
Bad White [126]
Finding the inverse function of

\mathsf{f(x)=10-x^2}


Remember that when you compose f with its inverse \mathsf{f^{-1}}, you'll get the identity function:

\mathsf{(f\circ f^{-1})(x)=x}\\\\ \mathsf{f\big[f^{-1}(x)\big]=x}\\\\


So if

\mathsf{f(x)=10-x^2}


then

\mathsf{f\big[f^{-1}(x)\big]=10-[f^{-1}(x)]^2}\\\\ \mathsf{x=10-[f^{-1}(x)]^2}\\\\ \mathsf{[f^{-1}(x)]^2=10-x}\\\\ \mathsf{f^{-1}(x)=\pm \sqrt{10-x}}\\\\ \mathsf{f^{-1}(x)=-\sqrt{10-x}~~~or~~~f^{-1}(x)=\sqrt{10-x}}


The sign of the inverse depends on the domain of \mathsf{f(x)} itself, and where it's invertible.


If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2198197


I hope this helps.


Tags: <em>inverse function definition identity domain algebra</em>

3 0
3 years ago
Orange M&amp;M’s: The M&amp;M’s web site says that 20% of milk chocolate M&amp;M’s are orange. Let’s assume this is true and set
SOVA2 [1]

Answer:

The correct option is (A).

Step-by-step explanation:

Let <em>X</em> = number of orange  milk chocolate M&M’s.

The proportion of orange milk chocolate M&M’s is, <em>p</em> = 0.20.

The number of candies in a small bag of milk chocolate M&M’s is, <em>n</em> = 55.

The event of an milk chocolate M&M being orange is independent of the other candies.

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 55 and <em>p</em> = 0.20.

The expected value of a Binomial random variable is:

E(X)=np

Compute the expected number of orange  milk chocolate M&M’s in a bag of 55 candies as follows:

E(X)=np

         =55\times 0.20\\=11

It is provided that in a randomly selected bag of milk chocolate M&M's there were 14 orange ones, i.e. the proportion of orange milk chocolate M&M's in a random bag was 25.5%.

This proportion is not surprising.

This is because the average number of orange milk chocolate M&M’s in a bag of 55 candies is expected to be 11. So, if a bag has 14 orange milk chocolate M&M’s it is not unusual at all.

All unusual events have a very low probability, i.e. less than 0.05.

Compute the probability of P (X ≥ 14) as follows:

P(X\geq 14)=\sum\limits^{55}_{x=14}{{55\choose x}0.20^{x}(1-0.20)^{55-x}}

                 =0.1968

The probability of having 14 or more orange candies in a bag of milk chocolate M&M’s is 0.1968.

This probability is quite larger than 0.05.

Thus, the correct option is (A).

4 0
4 years ago
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