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ale4655 [162]
3 years ago
9

The graphs of two functions, f (x) and g(x), where g(x) = f(x) + h, are shown.

Mathematics
1 answer:
taurus [48]3 years ago
6 0
Just see what you would add to f(x) get the graph of g(x)
It seems h(x) = 5
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Solve 7 ÷ one half = ___.<br> Question 1 options:<br><br> 14<br><br> 15<br><br> 24<br><br> 40
Norma-Jean [14]

Answer:

O 14

Step-by-step explanation:

hope it is helpful :)

7 0
3 years ago
What does the slope of the line represent within the context of my graph
Nata [24]
The slope of the line is the velocity, or rate of change, of y with respect to x.  In other terms, the slope tells you how much y will change for every change in x by one unit.  For example if the slope, which is velocity, is 2.  y will increase by two units every time x increases by one unit.  Your graph is not pictured nor explained, so I cannot give you the specific context beyond the principle that the slope of a line is a constant velocity or rate of change.
7 0
3 years ago
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Check whether the function yequalsStartFraction cosine 2 x Over x EndFraction is a solution of x y prime plus yequalsnegative 2
Jobisdone [24]

The question is:

Check whether the function:

y = [cos(2x)]/x

is a solution of

xy' + y = -2sin(2x)

with the initial condition y(π/4) = 0

Answer:

To check if the function y = [cos(2x)]/x is a solution of the differential equation xy' + y = -2sin(2x), we need to substitute the value of y and the value of the derivative of y on the left hand side of the differential equation and see if we obtain the right hand side of the equation.

Let us do that.

y = [cos(2x)]/x

y' = (-1/x²) [cos(2x)] - (2/x) [sin(2x)]

Now,

xy' + y = x{(-1/x²) [cos(2x)] - (2/x) [sin(2x)]} + ([cos(2x)]/x

= (-1/x)cos(2x) - 2sin(2x) + (1/x)cos(2x)

= -2sin(2x)

Which is the right hand side of the differential equation.

Hence, y is a solution to the differential equation.

6 0
4 years ago
Giving brainliest to anyone who answers
cricket20 [7]

D1=25°

B3=25°

B1=30°

Step-by-step explanation:

1. O1+O2=360°(revolution)

310°+O2=360°

O2=360°-310°

=50°

O2=2D1(centre theorem)

50°=2D1

D1=25°

2. D1=B3=25°(tan chord theorem)

3. B2+B3=A=60°(tan chord theorem)

B1+B2+B3=90°(Radius perpendicular Tangent)

B1+60°=90°

B1=90°-60°

=30°

5 0
3 years ago
(-2,11)slope -4 write the linear equation
kodGreya [7K]

Answer:

y = − 4 x + 3

Step-by-step explanation:

8 0
3 years ago
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