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Komok [63]
3 years ago
7

An aquarium tank can hold 7200 liters of water. there are two pipes that can be used to fill the tank. the first pipe alone can

fill the tank in 48 minutes. the second pipe can fill the tank in 96 minutes by itself. when both pipes are working together, how long does it take them to fill the tank?
Mathematics
1 answer:
Arada [10]3 years ago
4 0

The first pipe pumps out

\dfrac{7200\text{ L}}{48\text{ min}}=\dfrac{150\text{ L}}{1\text{ min}}

while the second pipe pumps out

\dfrac{7200\text{ L}}{96\text{ min}}=\dfrac{75\text{ L}}{1\text{ min}}

So together, both pipes pump out

\dfrac{150+75\text{ L}}{1\text{ min}}=\dfrac{225\text{ L}}{1\text{ min}}=\dfrac{7200\text{ L}}{32\text{ min}}

That is, with both pipes filling the tank, it should take 32 minutes total.

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The cost of painting the total outside surface of a closed cylindrical tank at 60 paise per meter squae is Rs237.60. The height
valkas [14]

Answer:

volume=509.25 dm^{3}

Step-by-step explanation:

Curved surface area=\frac {237.6}{0.6}=396 dm^{2}=2\pi R(R+H) where R is radius and H is height

Since H=6R then curved surface area=2\pi R(R+6R)=14\pi R^{2}

Therefore,  

396 dm^{2}=14\pi R^{2} and making R the subject

R=\sqrt {\frac {396}{14\pi}}=\sqrt {(9.003622)}= 3.000604 m

Therefore, H=6R=6*3.000604=18.00362 m

Volume=\pi R^{2}H=\pi*3.000604^{2}*18.00362=509.2453 dm^{3}

Therefore, volume=509.25 dm^{3}

6 0
2 years ago
Solve the following: Three times the 1st number plus the 2nd number plus twice the 3rd is 5. If three times the 2nd number is su
Karolina [17]
Three times the 1st number plus the 2nd number plus twice the 3rd is 5 is the same as 3x+y+2z=5. If three times the 2nd number is subtracted from the sum of the 1st and three times the 3rd number, the result is 2 is just x+3z-3y=2. And if the 3rd number is subtracted from two times the 1st number and three times the 2nd, giving a result of 1 means 2x+3y-z=1. Then you use substition on these equations to get a equation where one variable equals 2 others, like using the first to get y=5-2z-3x and then this can be substituted into the other two to get x+3z-3(5-2z-3x)=2 and 2x+3(5-2z-3x)-z=1 we can then simplify and subtract the equations. After simplification we have 10x+9z=17 and 7z+7x=16 which can be turned into 70x+63z=119 and 70x+70z=160 which can be then subtracted to get that 7z=41 and z=41/7. Now we backtrack to a two variable equation like 7z+7x=16 and plug in to find x. So after plugging in we get 41+7x=16 and 7x=-25 so x=-25/7. Now we choose a 3 variable equation and plug in. So taking y=5-2z-3x we plug in 41/7 for z and -25/7 for x to get y=5-82/7+75/7 and y=5-7/7 and y=4. Therefore x = -25/7 y = 4 and z = 41/7.
3 0
3 years ago
Find the exact values of sin2 θ for cos θ = 3/18 on the interval 0° ≤ θ ≤ 90°
mote1985 [20]

Answer:

sin(2\theta)=\frac{\sqrt{35} }{18}

Step-by-step explanation:

Recall the formula for the sine of the double angle:

sin(2\theta)=2*sin(\theta)*cos(\theta)

we know that cos(\theta)=\frac{3}{18}, and that \theta is in the interval between 0 and 90 degrees, where both the functions sine and cosine are non-negative numbers. Based on such, we can find using the Pythagorean trigonometric property that relates sine and cosine of the same angle, what sin(\theta) is:

cos^2(\theta)+sin^2(\theta)=1\\sin^2(\theta)=1-cos^2(\theta)\\sin(\theta)=\sqrt{1-cos^2(\theta)} \\sin(\theta)=\sqrt{1-(\frac{3}{18} )^2}\\sin(\theta)=\sqrt{1-\frac{9}{324} }\\sin(\theta)=\sqrt{\frac{324-9}{324} }\\sin(\theta)=\sqrt{\frac{315}{324} }\\\\sin(\theta)=\frac{3}{18}\sqrt{35 }

With this information, we can now complete the value of the sine of the double angle requested:

sin(2\theta)=2*sin(\theta)*cos(\theta)\\sin(2\theta)=2*\frac{3}{18} \,\sqrt{35} \,\frac{3}{18}\\sin(2\theta)=\frac{2*3*3}{18*18}\,\sqrt{35} \\sin(2\theta)=\frac{\sqrt{35} }{18}

6 0
3 years ago
Please help me with question #6!!!
Bumek [7]
Previous balance:

+ $481,47→ 11/30
- $300,00 → 11/02
- $68,99 → 11 / 10
- $45,00 → 11/15
- $72,75 → 11/17
----------------------------
+ $481,47 - $113,26 =
+ $368,21 

new balance:

+ $481,47→ 11/30
- $300,00 → 11/02
- $\diagup\!\!\!\! 68,\diagup\!\!\!\!99 → 11 / 10 for -$58,99
- $45,00 → 11/15
- $\diagup\!\!\!\! 72,\diagup\!\!\!\!75 → 11/17 for $ 0
-------------------------------------------------------------------------------------
+ $481,47 - $196,01 =
+$285,46 

Answer: 
\boxed{+285,46}
4 0
2 years ago
Please help I think I did something wrong if you can like…please re do it
Pachacha [2.7K]

Answer:

check image below

Step-by-step explanation:

6 0
1 year ago
Read 2 more answers
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