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Mashutka [201]
4 years ago
8

ANSWER FAST (look at picture for problem!) (number 6)

Mathematics
2 answers:
leva [86]4 years ago
7 0

Answer:

D is true A false

Step-by-step explanation:

Snezhnost [94]4 years ago
6 0
D

(btw you have really nice hand writing, lol)
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Combining like terms means to what
Cerrena [4.2K]

combining like terms means to get rid of one factor on both sides of the equation.

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Tell whether b=82 is a solution of b÷9=9
netineya [11]

Answer:

no, it's 81

Step-by-step explanation:

9×9=81 hope that this helps you and have a great day :)

5 0
3 years ago
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Please help .A spinner is divided into 6 equal sections. Each section is marked with one of the numbers 1 through 6. Miguel want
RUDIKE [14]

Answer:

The answer is C

Step-by-step explanation:

7 0
3 years ago
Explain why the two equations below have the same solutions.
Sladkaya [172]
The answer would be A the two equations have the same slope so they have the same solutions.
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5 0
3 years ago
Divide Rational Expressions<br> In the following exercises, divide.
guapka [62]

Answer:

\displaystyle \mathbf{\frac{5}{(c+4)}}

Step-by-step explanation:

<u>Division of Rational Expressions</u>

When dividing two rational expressions like f(c) / g(c), it's usually easier to multiply the numerator by the reciprocal of the denominator: f(c) * (1/g(c)). The reciprocal is just flipping the numerator and the denominator.

Let's find the following division:

\displaystyle \frac{\frac{c^2-64}{3c^2+26c+16}} {\frac{c^2-4c-32}{15c+10}}

First, we factor the polynomials where possible.

c^2-64 = (c-8)(c+8)

3c^2+26c+16=(3c+2)(c+8)

c^2-4c-32=(c-8)(c+4)

15c+10=5(3c+2)

Substituting:

\displaystyle \frac{\frac{c^2-64}{3c^2+26c+16}} {\frac{c^2-4c-32}{15c+10}}=\frac{\frac{(c-8)(c+8)}{(3c+2)(c+8)}} {\frac{(c-8)(c+4)}{5(3c+2)}}

Multiplying by the reciprocal of the denominator:

\displaystyle \frac{\frac{c^2-64}{3c^2+26c+16}} {\frac{c^2-4c-32}{15c+10}}=\frac{(c-8)(c+8)}{(3c+2)(c+8)}\cdot  \frac{5(3c+2)}{(c-8)(c+4)}

Simplifying by (c+8)(3c+2)(c-8):

\displaystyle \frac{\frac{c^2-64}{3c^2+26c+16}} {\frac{c^2-4c-32}{15c+10}}=\frac{5}{(c+4)}

Answer:

\displaystyle \mathbf{\mathbf{\frac{5}{(c+4)}}}

5 0
3 years ago
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