Answer:
0.9884 = 98.84% probability that the proportion of flops in a sample of 469 released films would be greater than 6%.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean and standard deviation
A film distribution manager calculates that 9% of the films released are flops.
This means that
Sample of 469
This means that
Mean and standard deviation:
What is the probability that the proportion of flops in a sample of 469 released films would be greater than 6%?
1 subtracted by the p-value of Z when X = 0.06. So
By the Central Limit Theorem
has a p-value of 0.0116
1 - 0.0116 = 0.9884
0.9884 = 98.84% probability that the proportion of flops in a sample of 469 released films would be greater than 6%.
